日期:2014-05-16  浏览次数:20743 次

Ajax无刷新实现定时更新数据
1、引用 ajax.dll 实现走动时间显示来查看效果

前台代码
<script language="javascript" type="text/javascript">
          //定时更新时间
          function refresh()
          {
               var div = document.all("divTime");
             
               var strTime = Default1.GetAllOnLineUser().value;
               if (strTime != "")
                   div.innerHTML = strTime;
                            
               //1秒钟刷新
               window.setTimeout(refresh, 1000);
          }

</script>
<body>
<form id="form1" runat="server">
    <div id="divTime"></div>
    <script>
        refresh();
    </script>    
    </form>
</body>

后台代码:

protected void Page_Load(object sender, EventArgs e)
{
         //注册Ajax类型
         Ajax.Utility.RegisterTypeForAjax(typeof(Default1));
}

    [Ajax.AjaxMethod()]
    public string GetAllOnLineUser()
    {      
        return "当前时间:" + DateTime.Now.ToString();
    }



2、使用 Ajax 控件实现定时刷新数据

HTML代码:
<body>
    <form id="form1" runat="server">
        <div>
            <asp:ScriptManager ID="ScriptManager1" runat="server">
            </asp:ScriptManager>
            <asp:UpdatePanel ID="UpdatePanel1" runat="server" ChildrenAsTriggers="true">
            <ContentTemplate>
                <asp:Timer ID="Timer1" runat="server" OnTick="Timer1_Tick" Interval="1000">
                </asp:Timer>
                <asp:GridView ID="GridView1" runat="server">
                </asp:GridView>
            </ContentTemplate>
            </asp:UpdatePanel>
        </div>
    </form>
</body>

后台代码:
    protected void Page_Load(object sender, EventArgs e)
  &n