日期:2014-05-16  浏览次数:20755 次

ajax判断是小 - Web 开发 / Ajax
我判断一个邮箱是否注册,无论输入什么邮箱都提示已注册,郁闷很。很焦急。
ajax.js
function send0()
{
createxmlrequesthttp();
var useremail=document.getElementById("uesremail").value;
  var ch=document.getElementById("useremail_info");
xmlhttp.open("get","find.asp?useremail0="+ escape(useremail) +"&t=" + new Date().getTime());
  xmlhttp.onreadystatechange=function()
  {
  if(4==xmlhttp.readyState)
  {
  if(200==xmlhttp.status)
  {
  if (xmlhttp.responseText=="yes")
  { 
  msg="ok";
  }
  else
  {
  msg="不存在此邮箱,请重新输入";
  }  
  }
  else
  {
  msg="网络链接失败";
  }
  var ch=document.getElementById("useremail_info");
  ch.innerHTML="<font color='#ff0000'>"+msg+"</font>";  
  }
  }
  xmlhttp.send(null);  
  return false;
}  
find.asp
<%
dim useremail
useremail=request("useremail0")
set rs=server.createobject("adodb.recordset")
rs.open "select * from [member] where [useremail]='" & useremail & "'",conn,1,1
if rs.eof then
 response.write "no"
else
 response.write "yes"
end if
rs.close
set rs=nothing
set conn=nothing '清空对象
%>

------解决方案--------------------
看下select * from [member] where [useremail]='" & useremail & "'"这个查询是不是对的。返回的什么值。然后再看下xmlhttp.responseText 的值。
------解决方案--------------------
试一下

JScript code
function send0()
{
createxmlrequesthttp();
var useremail=document.getElementById("uesremail").value;
    var ch=document.getElementById("useremail_info");
xmlhttp.open("get","find.asp?useremail0="+ escape(useremail) +"&t=" +  new Date().getTime());
      xmlhttp.send(null); 
xmlhttp.onreadystatechange=function()
  {
    if(4==xmlhttp.readyState)
      {
        if(200==xmlhttp.status)
        {
            if (xmlhttp.responseText=="yes")
            {
                msg="ok";
            }
            else
            {
                msg="不存在此邮箱,请重新输入";
            } 
        }
    else
    {
      msg="网络链接失败";
    }
    var ch=document.getElementById("useremail_info");
    ch.innerHTML=" <font color='#ff0000'>"+msg+" </font>";   
  }
  }

  return false;
}