<%@ Language=VBScript %>
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'几个参考点的数据已经给出，输入参数只有 X

function view(result,inputx)  '输出结果，同时如果<1 and >0,就在前面补0
  if result<1 and result>0 then result=0&result
  Response.Write "计算结果："&"<br>"
  Response.Write "F("&inputx&")="& result
end function


'********分段线性Lagrange插值**********
function Lagrange1(inputx)
dim k,i
dim x,y
x=array("0.1","0.2","0.3","0.4")
y=array("0.0998","0.1987","0.2955","0.3894")

if inputx<x(0) then k=0
if inputx>x(3) then k=2

for i=0 to 2
   if inputx>=x(i) and inputx<=x(i+1)  then k=i
   result=((inputx-x(k+1))/(x(k)-x(k+1)))*y(k) + ((inputx-x(k))/(x(k+1)-x(k)))*y(k+1)
next  
  result= view(result,inputx)
end function   




'********分段三点二次Lagrange插值**********
function Lagrange2(inputx)
dim i,j,k,t
dim x,y
result=0
x=array("0.1","0.2","0.3","0.4")
y=array("0.0998","0.1987","0.2955","0.3894")

if inputx<=x(1) then k=0
if inputx>=x(2) then k=1
if inputx>x(1) and inputx<x(2) and abs(inputx-x(1))<=abs(inputx-x(2)) then k=0 else k=1


for j=k to k+2
t=1
for i= k to k+2
   if i<>j then
   t= t * (inputx-x(i))/(x(j)-x(i))
   end if
next
   result = result + t*y(j)
next
result= view(result,inputx)
end function


'**********一元n点拉格朗日插值***********
function Lagrange3(inputx)
dim i,j
dim x,y
result=0
x=array("0","0.1","0.195","0.4","0.401","0.5")
y=array("0.39894","0.39695","0.39142","0.38138","0.36812","0.35206")

for j=0 to 5
t=1
for i=0 to 5
   if i<>j then
   t= t * (inputx-x(i))/(x(j)-x(i))
   end if
next
   result = result + t * y(j)
next
  result= view(result,inputx)
end function



'***********牛顿（Newton）插值***********
function Newton(inputx)
dim x,y
dim i,j
result=0.39894
t=1
x=array("0","0.1","0.195","0.3","0.401","0.5")
y=array("0.39894","0.39695","0.39142","0.38138","0.36812","0.35206")

for j=1 to 5
  t=t*(inputx - x(j-1))
  for i=0 to 5-j
    y(i)=(y(i+1) - y(i)) / (x(i+j) - x(i))
  next
    result = result + t * y(0)
next
   result= view(result,inputx)
end function


'***********埃特金（Aitken）插值***********
function Aitken(inputx)
dim i,j
dim x,y
x=array("0.5","0.65","0.8","1.0")
y=array("0.4794","0.6052","0.7174","0.8415")
for j=1 to 3
   for i=j to 3
   y(i)=y(j-1) + (y(i)-y(j-1)) / (x(i)-x(j-1))* (inpu