eval支持参数传递么？
eval(abc(1))

如何把这个参数1,传递进去?

------解决方案--------------------
n=1
eval( "abc( " + n + ") ");
------解决方案--------------------
function abc(num)
{
alert(num);
}

n=10;
eval( "abc( " + n + ") ");

------解决方案--------------------
Sub abc(n)
Response.Write n
End Sub
字符串
n= "xxx "
eval( "abc( " " " & n & " " ") ");
数字
n=1
eval( "abc( " & n & ") ");