如何将中文转换为这种码?
比如 "你好 "就是 "%C4%E3%BA%C3 "
提交form表单用get时就会出来.
如何用asp使中文变成这种码?

------解决方案--------------------
给你一段代码，不是你说那种，但差不多，都是加密URL的
'-------------------------------------------------
'函数功能：文字加密解密Base64算法
'加密函数：base64Encode(str) as String
'解密函数：base64Decode(str) as String
'-------------------------------------------------

const BASE_64_MAP_INIT = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/ "
dim nl
' zero based arrays
dim Base64EncMap(63)
dim Base64DecMap(127)

' must be called before using anything else
PUBLIC SUB initCodecs()
' init vars
nl = " <P> " & chr(13) & chr(10)
' setup base 64
dim max, idx
max = len(BASE_64_MAP_INIT)
for idx = 0 to max - 1
' one based string
Base64EncMap(idx) = mid(BASE_64_MAP_INIT, idx + 1, 1)
next
for idx = 0 to max - 1
Base64DecMap(ASC(Base64EncMap(idx))) = idx
next
END SUB

' encode base 64 encoded string
PUBLIC FUNCTION base64Encode(plain)
if len(plain) = 0 then
base64Encode = " "
exit function
end if
dim ret, ndx, by3, first, second, third
by3 = (len(plain) \ 3) * 3
ndx = 1
do while ndx <= by3
first = asc(mid(plain, ndx+0, 1))
second = asc(mid(plain, ndx+1, 1))
third = asc(mid(plain, ndx+2, 1))
ret = ret & Base64EncMap((first \ 4) AND 63 )
ret = ret & Base64EncMap(((first * 16) AND 48) + ((second \ 16) AND 15 ) )
ret = ret & Base64EncMap(((second * 4) AND 60) + ((third \ 64) AND 3 ) )
ret = ret & Base64EncMap(third AND 63)
ndx = ndx + 3
loop
' check for stragglers
if by3 < len(plain) then
first = asc(mid(plain, ndx+0, 1))
ret = ret & Base64EncMap((first \ 4) AND 63 )
if (len(plain) MOD 3 ) = 2 then
second = asc(mid(plain, ndx+1, 1))
ret = ret & Base64EncMap(((first * 16) AND 48) + ((second \16) AND 15 ))
ret = ret & Base64EncMap(((second * 4) AND 60))
else
ret = ret & Base64EncMap((first * 16) AND 48)
ret = ret & "= "
end if
ret = ret & "= "
end if
base64Encode = ret
END FUNCTION

' decode base 64 encoded string
PUBLIC FUNCTION base64Decode(scrambled)
if len(scrambled) = 0 then
base64Decode = " "
exit function
end if
' ignore padding
dim realLen
realLen = len(scrambled)
do while mid(scrambled, realLen, 1) = &quo