declare 
@g int = 1, @m int, @x int, @money int = 100
while (@money > 0)
begin 
    set @money = 100 - (@g*5) --剩下的钱
    set @m = 1 
    set @x = 1
    --二次循环
    while (@m <= @money/3)
    begin 
        set @x = 100 - @g*5 -@m*3    
        if @x <> 0    -- 这里不能有0 的情况    
        print '公鸡:'+convert(varchar(2),@g)+'母鸡:'+convert(varchar(2),@m)+'小鸡:'+convert(varchar(2),@x)
        set @m = @m +1
    end
    --将母鸡数量重置
    set @m = 1
    set @money = 100 - (@g*5)
    set @g = @g+1
end

------解决方案--------------------
应该是百元买百鸡
DECLARE @i INT;
DECLARE @j INT;
DECLARE @k INT;
SET @i = 0;
SET @j = 0;
SET @k = 0;
WHILE @i <= 20
 BEGIN
 	   set @j = 0;
 	   WHILE @j <= 33
 	   BEGIN  
 	   	SET  @k =0;
 	   	  WHILE @k <= 100
 	   	  BEGIN
 	   	  	  IF( @k%3=0 and @i * 5 + @j * 3 + @k/3 = 100  AND @i + @j + @k =100)
 	   	  	   begin
 	   	  			PRINT CAST(@i AS VARCHAR) + ' * 5 + ' + Cast(@j AS VARCHAR) + ' * 3 + ' + cast(@k AS VARCHAR) + ' * 1/3'
 	   	  			
 	   	  	  END
 	   	  	SET @k = @k + 1
 	   	  END
 	   	 SET @j = @j + 1
 	   END
 	   SET  @i = @i + 1
 END

输出:
0 * 5 + 25 * 3 + 75 * 1/3
4 * 5 + 18 * 3 + 78 * 1/3
8 * 5 + 11 * 3 + 81 * 1/3
12 * 5 + 4 * 3 + 84 * 1/3