求三级上拉菜单代码
日期：2014-05-17 浏览次数：20446 次
求三级下拉菜单代码
先不要数据库 只要查看页面和后台的详细代码就好 因为我还没创建数据库 吼吼 谢谢
------解决方案--------------------
这个是不需要连接数据库的，通过css和js实现的[code=HTML]<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=gb2312" />
<title>CSS+JS打造兼容性很好的三级导航菜单丨芯晴网页特效丨CsrCode.Cn</title>
<style>
.suckerdiv ul{
margin: 0;
padding: 0;
list-style-type: none;
width: 150px;
border-bottom: 1px solid #ccc;
}
.suckerdiv ul li{
position: relative;
}
.suckerdiv ul li ul{
left: 149px;
position: absolute;
width: 160px;
top: 0;
display: none;
}
.suckerdiv ul li ul li ul{
left: 159px;
}
.suckerdiv ul li a{
display: block;
color: black;
text-decoration: none;
font:12px 宋体;
background: #fff;
padding: 5px 5px;
border: 1px solid #ccc;
border-bottom: 0;
}
.suckerdiv ul li a:visited{
color: black;
}
.suckerdiv ul li a:hover{
color: white;
background-color: gray;
}
.suckerdiv .subfolderstyle{
background: url(http://www.codefans.net/jscss/demoimg/201201/arrow-list.gif) no-repeat center right;
}
* html .suckerdiv ul li { float: left; height: 1%; }
* html .suckerdiv ul li a { height: 1%; }
</style>
<script type="text/javascript">
var menuids=["suckertree1"] //Enter id(s) of SuckerTree UL menus, separated by commas
function buildsubmenus(){
for (var i=0; i<menuids.length; i++){
var ultags=document.getElementById(menuids[i]).getElementsByTagName("ul")
for (var t=0; t<ultags.length; t++){
ultags[t].parentNode.getElementsByTagName("a")[0].className="subfolderstyle"
ultags[t].parentNode.onmouseover=function(){
this.getElementsByTagName("ul")[0].style.display="block"
}
ultags[t].parentNode.onmouseout=function(){
this.getElementsByTagName("ul")[0].style.display="none"
}
}
}
}
if (window.addEventListener)
window.addEventListener("load", buildsubmenus, false)
else if (window.attachEvent)
window.attachEvent("onload", buildsubmenus)
</script>
</head>
<body>
<div class="suckerdiv">
<ul id="suckertree1">
<li><a href="#">Item 1</a></li>
<li><a href="#">Item 2</a></li>
<li><a href="#">Folder 1</a>
<ul>
<li><a href="#">Sub Item 1.1</a></li>
<li><a href="#">Sub Item 1.2</a></li>
</ul>
</li>
<li><a href="#">Item 3</a></li>
<li><a href="#">Folder 2</a>
<ul>
<li><a href="#">Sub Item 2.1</a></li>
<li><a href="#">Folder 2.1</a>
<ul>
<li><a href="#">Sub Item 2.1.1</a></li>
<li><a href="#">Sub Item 2.1.2</a></li>
<li><a href="#">Sub Item 2.1.3</a></li>
<li><a href="#">Sub Item 2.1.4</a></li>
</ul>
</li>
</ul>
</a>
</li>
<li><a href="#">Item 4</a></li>
</ul>
</div>
</body>
</html>
<br><br><hr>
先不要数据库 只要查看页面和后台的详细代码就好 因为我还没创建数据库 吼吼 谢谢
------解决方案--------------------
这个是不需要连接数据库的，通过css和js实现的[code=HTML]<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=gb2312" />
<title>CSS+JS打造兼容性很好的三级导航菜单丨芯晴网页特效丨CsrCode.Cn</title>
<style>
.suckerdiv ul{
margin: 0;
padding: 0;
list-style-type: none;
width: 150px;
border-bottom: 1px solid #ccc;
}
.suckerdiv ul li{
position: relative;
}
.suckerdiv ul li ul{
left: 149px;
position: absolute;
width: 160px;
top: 0;
display: none;
}
.suckerdiv ul li ul li ul{
left: 159px;
}
.suckerdiv ul li a{
display: block;
color: black;
text-decoration: none;
font:12px 宋体;
background: #fff;
padding: 5px 5px;
border: 1px solid #ccc;
border-bottom: 0;
}
.suckerdiv ul li a:visited{
color: black;
}
.suckerdiv ul li a:hover{
color: white;
background-color: gray;
}
.suckerdiv .subfolderstyle{
background: url(http://www.codefans.net/jscss/demoimg/201201/arrow-list.gif) no-repeat center right;
}
* html .suckerdiv ul li { float: left; height: 1%; }
* html .suckerdiv ul li a { height: 1%; }
</style>
<script type="text/javascript">
var menuids=["suckertree1"] //Enter id(s) of SuckerTree UL menus, separated by commas
function buildsubmenus(){
for (var i=0; i<menuids.length; i++){
var ultags=document.getElementById(menuids[i]).getElementsByTagName("ul")
for (var t=0; t<ultags.length; t++){
ultags[t].parentNode.getElementsByTagName("a")[0].className="subfolderstyle"
ultags[t].parentNode.onmouseover=function(){
this.getElementsByTagName("ul")[0].style.display="block"
}
ultags[t].parentNode.onmouseout=function(){
this.getElementsByTagName("ul")[0].style.display="none"
}
}
}
}
if (window.addEventListener)
window.addEventListener("load", buildsubmenus, false)
else if (window.attachEvent)
window.attachEvent("onload", buildsubmenus)
</script>
</head>
<body>
<div class="suckerdiv">
<ul id="suckertree1">
<li><a href="#">Item 1</a></li>
<li><a href="#">Item 2</a></li>
<li><a href="#">Folder 1</a>
<ul>
<li><a href="#">Sub Item 1.1</a></li>
<li><a href="#">Sub Item 1.2</a></li>
</ul>
</li>
<li><a href="#">Item 3</a></li>
<li><a href="#">Folder 2</a>
<ul>
<li><a href="#">Sub Item 2.1</a></li>
<li><a href="#">Folder 2.1</a>
<ul>
<li><a href="#">Sub Item 2.1.1</a></li>
<li><a href="#">Sub Item 2.1.2</a></li>
<li><a href="#">Sub Item 2.1.3</a></li>
<li><a href="#">Sub Item 2.1.4</a></li>
</ul>
</li>
</ul>
</a>
</li>
<li><a href="#">Item 4</a></li>
</ul>
</div>
</body>
</html>
<br><br><hr>
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