日期:2014-05-17 浏览次数:20434 次
<script language="javascript" type="text/javascript"> $(function(){ $("#Button1").click(function(){ $.post("text.aspx",{Action:"post",timeBegin:$("#TextBox1").val(),timeEnd:$("#TextBox2").val()} ,function(data){ document.getElementById("mydiv").innerHTML="<font color='red'>"+ data + "</font>"; },"json" ); }); }); </script> <form id="form1" runat="server"> <div> 起始日期:<asp:TextBox ID="TextBox1" class="mydate" runat="server"></asp:TextBox> 截止日期: <asp:TextBox ID="TextBox2" class="mydate" runat="server"></asp:TextBox> </div> <input id="Button1" type="button" value="提交" /> </form> <div id="mydiv"> </div>
protected void Page_Load(object sender, EventArgs e) { string timeBegin = Request.Form["timeBegin"]; string timeEnd = Request.Form["timeEnd"]; Response.ContentType = "text/plain"; Context.Response.Write("success!"); Response.End(); }
$(function(){ $("#Button1").click(function(){ $.post("text.aspx",{"Action":"post","timeBegin":$("#TextBox1").val(),"timeEnd":$("#TextBox2").val()} ,function(data){ document.getElementById("mydiv").innerHTML="<font color='red'>"+ data + "</font>"; },"json" ); }); });
------解决方案--------------------
"json" 你的反回值不是JSON 换成"text" 看看