------解决方案-------------------- select name from 表 where name like %相似%
------解决方案--------------------
------解决方案-------------------- 将查询字段用字符串处理下,“想找”这种应该是智能关键字吧 select name from A where name like '%相似%'
------解决方案-------------------- select * from A where name like '%" + TextBox1.Text + "%'