校验日期的函数
1.校验日期
<script language=javascript>
function isdate(str)
{
var r = str.match(/^(\d{1,4})(-\/)(\d{1,2})\2(\d{1,2})$/);
if(r==null)return false; var d = new date(r[1], r[3]-1, r[4]);
return (d.getfullyear()==r[1]&&(d.getmonth()+1)==r[3]&&d.getdate()==r[4]);
}
alert(isdate("2002-01-31"));
alert(isdate("2002-01-41"));
</script>
2.校验日期加时间
<script language=javascript>
function istime(str)
{
var r = str.match(/^(\d{1,4})(-\/)(\d{1,2})\2(\d{1,2}) (\d{1,2}):(\d{1,2}):(\d{1,2})$/);
if(r==null)return false; var d = new date(r[1], r[3]-1,r[4],r[5],r[6],r[7]);
return (d.getfullyear()==r[1]&&(d.getmonth()+1)==r[3]&&d.getdate()==r[4]&&d.gethours()==r[5]&&d.getminutes()==r[6]&&d.getseconds()==r[7]);
}
alert(istime("2002-1-31 12:34:56"));
alert(istime("2001-2-29 12:54:56"));
alert(istime("2002-1-41 12:00:00"));
</script>

------解决方案--------------------
正则：
C# code
        string s = "1986/4/11 0:00:00";
        Match match = Regex.Match(s, @"\d{4}/(?<month>\d{1,2})/(?<day>\d{1,2})");
        if (match.Groups["month"].Value == DateTime.Now.Month.ToString() && match.Groups["day"].Value == DateTime.Now.Day.ToString())
            Response.Write("生日快乐！");

------解决方案--------------------
C# code
Regex re = new Regex(@"/[\d]{1,2}/[\d]{1,2}");
            string sr = "1986/4/11 0:00:00";
            string a = re.Matches(sr)[0].ToString();
            string b = re.Matches(DateTime.Now.ToShortDateString())[0].ToString();
            if (a==b)
            {
                Console.WriteLine("Happy");
            }

------解决方案--------------------
[code=Java][/code]
       String sr = "(\\d{4})([09]|[9])[27]";
       Pattern p = Pattern.compile(sr);
       Matcher m = p.matcher("20100927");
       if(m.find()){
           System.out.println("OK");
       }else{
          
           System.out.println("NO");
       }

------解决方案--------------------
[code=Java][/code]
       String sr = "(\\d{4})([09]|[9])[27]";
       Pattern p = Pattern.compile(sr);
       Matcher m = p.matcher("20100927");
       if(m.find()){
           System.out.println("OK");
       }else{
          
           System.out.println("NO");
       }

------解决方案--------------------
C# code

string time="1986/9/27 0:00:00";
    Regex reg=new Regex(@"\d{4}/(\d{1,2})/(\d{1,2})");
    if(reg.IsMatch(time) && reg.Match(time).Groups[1].Value==DateTime.Now.Month.ToString() && 
    reg.Match(time).Groups[2].Value==DateTime.Now.Day.ToString() )
    {
      Console.WriteLine("Happy Birthday");
    }

------解决方案--------------------
[code=Java][/code]		// 1986/9/27 0:00:00
		SimpleDateFormat sdf = new SimpleDateFormat("yyyyMMdd HH:mm");
		String s="1986/9/27 0:00:00";
		String sraaa = sdf.format(new Date(s));
		String sr = "(\\d{4})([" + sraaa.substring(4,6) + "])[" + sraaa.substring(6,8) + "]";
		System.out.println(sr);
		//String sr = "(\\d{4})([09]|[9])[27]";