日期:2014-05-18  浏览次数:20499 次

ASP.NET+SQLServer上传并显示照片
开发工具:VS2005
数据库:SQLServer2000
开发语言:C#
问题:在一个ASP.Net页中实现上传照片并存入数据库,上传后显示所上传的照片,以后每次登录到相关页面时都会读取出此照片并显示出来
请大家说得详细些,易懂些

------解决方案--------------------
干吗不存在本地硬盘就好,再用路径把它取出来,
存到数据库的,占用数据库容量挺大的
------解决方案--------------------
直接在服务端建个文件夹,这样直接上传到该文件夹,就像一楼说的那样,用路径把它读取出来!
------解决方案--------------------
建议你看我发过的帖子,我发过的帖子有跟你一样的问题,在我的帖子里有贴我的代码。
代码只是一个思路!
------解决方案--------------------
C# code


using System;
using System.Data;
using System.Configuration;
using System.Web;
using System.Web.Security;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Web.UI.WebControls.WebParts;
using System.Web.UI.HtmlControls;

using System.IO;
using System.Data.SqlClient;

public partial class _Default : System.Web.UI.Page 
{
    protected void Page_Load(object sender, EventArgs e)
    {
        
    }
    protected void Button1_Click(object sender, EventArgs e)
    {

        #region 测试写入

        if (!FileUpload1.HasFile)
        {
            Response.Write("请选择图片");
        }

            string fileEx = System.IO.Path.GetExtension(this.FileUpload1.FileName);  //获取图片扩展名

            if (fileEx != ".gif" && fileEx != ".jpg" && fileEx != ".jpeg" && fileEx!= ".bmp")
            {
                Response.Write("只能上传图片");

            }


            else
            {

                
                    // ImageType 有用,读取图片的时候需要

                     int imgSize = this.FileUpload1.PostedFile.ContentLength;  //图片大小 (字节)
                    string imgType = this.FileUpload1.PostedFile.ContentType;    //图片类型
                    string imgPath = this.FileUpload1.PostedFile.FileName; //获取图片路径
                    string imgName = this.FileUpload1.FileName; //获取图片名字
                    int imgLength = this.FileUpload1.FileName.Length; //获取图片长度
                    if (imgLength <= 0)//判断是否有图片
                        return;
                    Byte[] imgByte = new Byte[imgSize]; //用图片的长度来初始化一个字节数组存储临时的图片文件
                    Stream stream = this.FileUpload1.PostedFile.InputStream; //建立文件流对象
                    stream.Read(imgByte, 0, imgSize);// 读取图片数据到临时存储体imgByte,0为数据指针位置,fileLength为数据长度
                    //this.FileUpload1.FileBytes
                    try
                    {
                        string connection = ConfigurationManager.ConnectionStrings["DBConn"].ConnectionString;
                        SqlConnection sqlconn = new SqlConnection(connection);
                        sqlconn.Open();
                        string sqlcmd = "insert into Image values (@ImageType,@ImageData,@ImageTitle)";
                        SqlCommand sqc =

------解决方案--------------------
C# code


using System;
using System.Data;
using System.Configuration;
using System.Collections;
using System.Web;
using System.Web.Security;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Web.UI.WebControls.WebParts;
using System.Web.UI.HtmlControls;

using System.IO;
using System.Data.SqlClient;

public partial class Default2 : System.Web.UI.Page
{
    protected void Page_Load(object sender, EventArgs e)
    {
        if (!Page.IsPostBack)
        {
            #region  测试读取
            string sqlCmd = "select top 1 * from Image order by imageID desc";
            string connection = ConfigurationManager.ConnectionStrings["DBConn"].ConnectionString;
            SqlConnection sqlconn = new SqlConnection(connection);
            try
            {
                sqlconn.Open();
                SqlCommand sqc = new SqlCommand(sqlCmd, sqlconn);

                //Response.ContentType = "image/pjpeg";
                using (SqlD