treeview 中window。open（）问题
本人编写了一段关于treeview的客户端脚本,打开一个新的窗口,但打开后的窗口却是显示在后面,有什么办法使新打开的窗口显示在最前面,其它按纽打开的窗口都是显示在最前面的.有什么办法呢?  
   
  代码如下:  
   
  function Tree_Click()  
  {  
  FolderID = tvContent.getTreeNode(tvContent.clickedNodeIndex).getAttribute("ID");  
  if (FolderID.substring(0,5) == "Works")  
  {  
  tmpwin = window.open("./flow/flow_AddNew.aspx?flowmodelid=1001","新流程" + opencount++,"scrollbars=yes,resizable=yes,top=0,left=0,width="+(window.availWidth-12)+",height="+(window.availHeight-35));  
  window.Content.tvContent.blur();  
  if(tmpwin != null)  
  tmpwin.focus();  
   
   
   
  }  
  }  
   


------解决方案--------------------
tmpwin.opener.blur();
tmpwin.focus();
------解决方案--------------------
function Tree_Click()
{
FolderID = tvContent.getTreeNode(tvContent.clickedNodeIndex).getAttribute("ID");
if (FolderID.substring(0,5) == "Works")
{
tmpwin = window.open("./flow/flow_AddNew.aspx?flowmodelid=1001","新流程" + opencount++,"scrollbars=yes,resizable=yes,top=0,left=0,width="+(window.availWidth-12)+",height="+(window.availHeight-35));
tmpwin.focus();



}
}
------解决方案--------------------
加一个 return false; 触发时用 return