会asp.net ajax的请进。
<div   id= "div1 "   runat= "server ">
    <updateprogress> ......
</div>
<div   id= "div2 "   runat= "server ">
    <updatepanel>
          <asp:textbox   runat= "server "   id= "textbox1 ">
          <asp:button   onclick= "button_click "   onclick= "clentclikc(); ">
    </updatepanel>
<div>

function   clentclikc()
{
        document.getElementById( "div1 ").style.disyplay= "block ";
        document.getElementById( "div2 ").style.disyplay= "none ";
}

public   void   button_click()
{
      if(textbox1.text== "abc ")
      {
              ....
      }
      else
      {
              .....
      }
}
问题1：当textbox1.text= "abc "时，如何让div1显示信息。
问题2：当textbox1.text <> "abc "时，如何先提示用户出错，再显示让div2从新显示出来。

------解决方案--------------------
<div id= "div1 " runat= "server ">
<updateprogress> ......
</div>
<div id= "div2 " runat= "server ">
<updatepanel>
<asp:textbox runat= "server " id= "textbox1 ">
<asp:button onclick= "button_click ">
</updatepanel>
<div>

public void button_click()
{
if(textbox1.text== "abc ")
{
div1.Visible = true;
div2.Visible = false;
}
else
{
div1.Visible = false;
div2.Visible = true;
}
}

------解决方案--------------------
这个貌似用不着AJAX

<div id= "div1 " runat= "server ">
<updateprogress> ......
</div>
<div id= "div2 " runat= "server ">
<updatepanel>
<asp:textbox runat= "server " id= "textbox1 ">
<asp:button onclick= "button_click " onclick= "clentclikc(); ">
</updatepanel>
<div>


public void button_click()
{
if(textbox1.text== "abc ")
{
Div1.Disabled = true;
　　　Div2.Disabled = false;
}
else
{
Div1.Disabled = true;
　　　　Div2.Disabled = false;
}
}
------解决方案--------------------
javascript就能搞定了吧

------解决方案--------------------
恩，js搞定的