新手问题,高手帮忙
ajax调用xmlhttp.open( "GET ", "WebForm2.aspx ", true)的页面只有一句代码
Response.Write( "222 ");
但是xmlhttp.responseText返回了
【222
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN " > <HTML> <HEAD> <title> WebForm2 </title> <meta name= "GENERATOR " Content= "Microsoft Visual Studio .NET 7.1 "> <meta name= "CODE_LANGUAGE " Content= "C# "> <meta name= "vs_defaultClientScript " content= "JavaScript "> <meta name= "vs_targetSchema " content= "http://schemas.microsoft.com/intellisense/ie5 "> </HEAD> <body MS_POSITIONING= "GridLayout "> <form name= "Form1 " method= "post " action= "WebForm2.aspx " id= "Form1 "> <input type= "hidden " name= "__VIEWSTATE " value= "dDwtNjU0MzcyMTk1Ozs+We1PBSx8xnLidHX4fwEcLek3NUo= " /> </form> </body> </HTML> 】
有什么办法能不返回后面的HTML代码吗?
------解决方案--------------------Response.Write( "222 ");
Response.End();
代码放到什么地方了,要放到Page_Load里面的