弹出窗口
我想   在打开   一个页面的时候,   然后过几秒钟后   ,在桌面的右下角   弹出一个   提示消息   的   小窗体   该怎么做,希望大哥大姐们   给我点提示,谢谢啦!

------解决方案--------------------
没做过
用javascript弹出来个IE窗口,改变一下样式,和位置应该可以吧

------解决方案--------------------
setTimeout(事件,时间)
------解决方案--------------------
<script>

var oPopup = window.createPopup();

var popTop=50;

function popmsg(msgstr){

var winstr= " <table style=\ "border: 1 solid #FFA6CA\ " width=\ "241\ " height=\ "172\ " border=\ "0\ " cellpadding=\ "0\ " cellspacing=\ "0\ " background=\ "背景图片地址\ " > ";

winstr+= " <tr> <td height=\ "30\ "> </td> </tr> <tr> <td align=\ "center\ "> <table width=\ "90%\ " height=\ "110\ " border=\ "0\ " cellpadding=\ "0\ " cellspacing=\ "0\ "> ";

winstr+= " <tr> <td valign=\ "top\ " style=\ "font-size:文字大小; color: 文字颜色; face: Tahoma\ ">  "+msgstr+ " </td> </tr> </table> </td> </tr> </table> ";

oPopup.document.body.innerHTML = winstr;

popshow();

}

function popshow(){

window.status=popTop;

if(popTop> 1720){

clearTimeout(mytime);

oPopup.hide();

return;

}else if(popTop> 1520&&popTop <1720){

oPopup.show(screen.width-250,screen.height,241,1720-popTop);

}else if(popTop> 1500&&popTop <1520){

oPopup.show(screen.width-250,screen.height+(popTop-1720),241,172);

}else if(popTop <180){

oPopup.show(screen.width-250,screen.height,241,popTop);

}else if(popTop <220){

oPopup.show(screen.width-250,screen.height-popTop,241,172);

}

popTop+=10;

var mytime=setTimeout( "popshow(); ",20);

}

popmsg( "弹出内容! ");

</script>