求助:一个关于绑定按钮列弹出新页面的问题~百分相赠!
我用DATAGRID绑定了一个按钮列,当点击该按钮时,要求打开一个新页面并传递一个值同时不能覆盖掉原来的页面,代码如下:我需要如何修改~~请高手指点~~
Private Sub DataGrid1_ItemCommand(ByVal source As System.Object, ByVal e As System.Web.UI.WebControls.DataGridCommandEventArgs) Handles Datagrid1.ItemCommand
Dim row As DataRow
Try
If e.Item.ItemType <> ListItemType.Pager Then
If e.CommandName = "Select " Then
Dim no As String = e.Item.Cells(0).Text
Response.Redirect( "Form/NoteEditForm.aspx?parm0= " + no, True)
End If
End If
Catch ex As Exception
MyLog.Log(LogLevel.ErrorLevel, ex)
Message(ex.Message)
End Try
End Sub
------解决方案--------------------up
------解决方案--------------------用JS来open一个不好吗?修改弹出页面的样式,就可以不显示状态栏,地址栏之类的了
------解决方案--------------------页面上 <head> </head> 之间加
<SCRIPT LANGUAGE= "JavaScript ">
<!--
function winOpen(__URL)
{
window.open(__URL, "NewPage ", "toolbar=no,menubar=no,resizable=yes, scrollbars=yes,top=50px,left=100 ");
}
//-->
</SCRIPT>
Response.Redirect( "Form/NoteEditForm.aspx?parm0= " + no, True)
--> >
Page.RegisterStartupScript( "winop ", " <script> winopen( ' "+ "Form/NoteEditForm.aspx?parm0= " + no+ " '); </script> ");
------解决方案--------------------If e.Item.ItemType <> ListItemType.Pager Then
If e.CommandName = "Select " Then
Dim no As String = e.Item.Cells(0).Text
Dim btnShow As Button = e.Item.Cells(0).FindControl( "BtnId ")
btnShow.Attributes.Add( &qu