现在有很多的xml工具软件都能根据xsd文件书写出xml文档，.net 没有实现此方法，如是我写了几个浏览、校验、和创建xml的方法
全部代码如下：

using System;
using System.Data;
using System.Configuration;
using System.Web;
using System.Web.Security;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Web.UI.WebControls.WebParts;
using System.Web.UI.HtmlControls;
using System.Xml;
using System.Xml.Schema;
using System.Collections;

/**//// <summary>
/// ProXML 的摘要说明
/// </summary>
public class ProXml
{
    public ProXml()
    {
        //
        // TODO: 在此处添加构造函数逻辑
        //
    }
    /**//// <summary>
    /// 获得xsd文件路径
    /// </summary>
    public static string GetSchemaPath
    {
           get{
               return HttpContext.Current.Request.PhysicalApplicationPath + "App_Data\\system\\publish.xsd";
           }
    }
    /**//// <summary>
    /// 获理节点
    /// </summary>
    /// <returns></returns>
    public static System.Collections.Generic.List<XmlSchemaElement> GetDatas()
    {
        XmlSchemaSet xsSet = new XmlSchemaSet();
        xsSet.Add("http://www.w3.org/2001/XMLSchema", GetSchemaPath);
        xsSet.Compile();
        XmlSchema schema = null;
        foreach (XmlSchema xs in xsSet.Schemas())
        {
            schema = xs;
        }
        System.Collections.Generic.List<XmlSchemaElement> elements=new System.Collections.Generic.List<XmlSchemaElement> ();
        foreach (XmlSchemaObject obj in schema.Elements.Values)
        {
            if (obj.GetType() == typeof(XmlSchemaElement))
            {
                elements.Add((XmlSchemaElement)obj);
            }

        }
        return elements;
     
    }
    /**//// <summary>
    /// 添加元素
    /// </summary>
    /// <param name="sourceXsd"></param>
    /// <param name="titles"></param>
    /// <param name="sourceXml"></param>
    /// <param name="sourceNd"></param>
    /// <param name="values"></param>
    public static   void AddElement(XmlSchemaObject sourceXsd, Hashtable titles, XmlDocument sourceXml, XmlNode sourceNd, string[] values)
    {

        if (sourceXsd.GetType() == typeof(Xml