利用OleDb对象，将数据库中全部表转换成XML文件
日期：2012-05-05 浏览次数：20443 次
ASP.NET Dataset让你在页面中使用XML格式的文件提供了便利。如果您的数据全部都在一个数据库中，该如何进行转换呢？如果你的数据库与OleDb兼容的话，下面就看看如何把数据库中的所有表转换成XML文件。文件名字与数据库中的表的名字相同。本代码包含两个版本：C#版本和VB.NET版本。
C#版本：
<%@ Page Language="C#" %>
<%@ import Namespace="System" %>
<%@ import Namespace="System.Data" %>
<%@ import Namespace="System.Data.OleDb" %>
<script runat="server">
void Page_Load(object sender, EventArgs e) {
if (!IsPostBack) {
TextBox1.Text = "PROVIDER=SQLOLEDB; Data Source=.; Initial Catalog=pubs;User ID=sa;Password=;";
Label1.Text = "";
}
}
void CreateXml(object sender, EventArgs e) {
OleDbConnection dataConn = new OleDbConnection(TextBox1.Text);
Uri Path = Request.Url;
String ServerUrl = Path.ToString();
ServerUrl = ServerUrl.Substring(0,ServerUrl.LastIndexOf("/") +1 );
try {
Literal1.Text = "已经在你的相同目录下创建了一下文件：<br/>" ;
dataConn.Open();
DataTable schemaTable = dataConn.GetOleDbSchemaTable(OleDbSchemaGuid.Tables,new object[] {null, null, null, "TABLE"});
for(int I = 0; I < schemaTable.Rows.Count; I++){
OleDbDataAdapter dbAdapter= new OleDbDataAdapter("select * from [" + schemaTable.Rows[I].ItemArray[2].ToString() + "]",dataConn);
DataSet tableData = new DataSet();
dbAdapter.Fill(tableData,schemaTable.Rows[I].ItemArray[2].ToString());
tableData.WriteXml(HttpContext.Current.Server.MapPath(schemaTable.Rows[I].ItemArray[2].ToString() + ".xml"));
Literal1.Text = Literal1.Text + "<a href='" + ServerUrl + schemaTable.Rows[I].ItemArray[2].ToString() + ".xml'>" + schemaTable.Rows[I].ItemArray[2].ToString() + ".xml</a><br/>";
}
}
catch(Exception ex) {
Label1.Text = ex.Message.ToString();
}
finally {
dataConn.Close();
}
}
</script>
<html>
<head>
<title>leDb2XML：数据库转换成XML文件例子</title>
</head>
<body bgcolor="#FFFFFF">
<center>
<h2><font face="宋体">OleDb2XML：数据库转换成XML文件例子</font>
</h2>
</center>
<form runat="server">
<font face="宋体">
<p align="center">请输入OleDb连接字符串，然后点“生成XML文件”按钮。</p>
<p align="center">
<asp:TextBox id="TextBox1" runat="server" Width="600"></asp:TextBox>
</p>
<p align="center">
<asp:Button id="Button1" onclick="CreateXml" runat="server" Text="生成XML文件"></asp:Button>
</p>
<p align="center">
<asp:Label id="Label1" runat="server" Font-Bold="True" ForeColor="Red"></asp:Label>
</p>
<p align="center">
<asp:Literal id="Literal1" runat="server"></asp:Literal>
</p>
</font>
</form>
</body>
</html>
VB.NET版本：
<%@ Page Language="VB" %>
<%@ import Namespace="System" %>
<%@ import Namespace="System.Data" %>
<%@ import Namespace="System.Data.OleDb" %>
<script runat="server">
Sub Page_Load(sender As Object, e As EventArgs)
If Not IsPostBack Then
TextBox1.Text = "Provider=SqlOLEDB; Data Source=.; Initial Catalog=pubs;User ID=sa;Password=;"
Label1.Text = ""
End If
End Sub
Sub CreateXml(sender As Object, e As EventArgs)
Dim dataConn As New OleDbConnection(TextBox1.Text)
Dim Path As Uri = Request.Url
Dim ServerUrl As String = Path.ToString()
ServerUrl = ServerUrl.Substring(0,Se
C#版本：
<%@ Page Language="C#" %>
<%@ import Namespace="System" %>
<%@ import Namespace="System.Data" %>
<%@ import Namespace="System.Data.OleDb" %>
<script runat="server">
void Page_Load(object sender, EventArgs e) {
if (!IsPostBack) {
TextBox1.Text = "PROVIDER=SQLOLEDB; Data Source=.; Initial Catalog=pubs;User ID=sa;Password=;";
Label1.Text = "";
}
}
void CreateXml(object sender, EventArgs e) {
OleDbConnection dataConn = new OleDbConnection(TextBox1.Text);
Uri Path = Request.Url;
String ServerUrl = Path.ToString();
ServerUrl = ServerUrl.Substring(0,ServerUrl.LastIndexOf("/") +1 );
try {
Literal1.Text = "已经在你的相同目录下创建了一下文件：<br/>" ;
dataConn.Open();
DataTable schemaTable = dataConn.GetOleDbSchemaTable(OleDbSchemaGuid.Tables,new object[] {null, null, null, "TABLE"});
for(int I = 0; I < schemaTable.Rows.Count; I++){
OleDbDataAdapter dbAdapter= new OleDbDataAdapter("select * from [" + schemaTable.Rows[I].ItemArray[2].ToString() + "]",dataConn);
DataSet tableData = new DataSet();
dbAdapter.Fill(tableData,schemaTable.Rows[I].ItemArray[2].ToString());
tableData.WriteXml(HttpContext.Current.Server.MapPath(schemaTable.Rows[I].ItemArray[2].ToString() + ".xml"));
Literal1.Text = Literal1.Text + "<a href='" + ServerUrl + schemaTable.Rows[I].ItemArray[2].ToString() + ".xml'>" + schemaTable.Rows[I].ItemArray[2].ToString() + ".xml</a><br/>";
}
}
catch(Exception ex) {
Label1.Text = ex.Message.ToString();
}
finally {
dataConn.Close();
}
}
</script>
<html>
<head>
<title>leDb2XML：数据库转换成XML文件例子</title>
</head>
<body bgcolor="#FFFFFF">
<center>
<h2><font face="宋体">OleDb2XML：数据库转换成XML文件例子</font>
</h2>
</center>
<form runat="server">
<font face="宋体">
<p align="center">请输入OleDb连接字符串，然后点“生成XML文件”按钮。</p>
<p align="center">
<asp:TextBox id="TextBox1" runat="server" Width="600"></asp:TextBox>
</p>
<p align="center">
<asp:Button id="Button1" onclick="CreateXml" runat="server" Text="生成XML文件"></asp:Button>
</p>
<p align="center">
<asp:Label id="Label1" runat="server" Font-Bold="True" ForeColor="Red"></asp:Label>
</p>
<p align="center">
<asp:Literal id="Literal1" runat="server"></asp:Literal>
</p>
</font>
</form>
</body>
</html>
VB.NET版本：
<%@ Page Language="VB" %>
<%@ import Namespace="System" %>
<%@ import Namespace="System.Data" %>
<%@ import Namespace="System.Data.OleDb" %>
<script runat="server">
Sub Page_Load(sender As Object, e As EventArgs)
If Not IsPostBack Then
TextBox1.Text = "Provider=SqlOLEDB; Data Source=.; Initial Catalog=pubs;User ID=sa;Password=;"
Label1.Text = ""
End If
End Sub
Sub CreateXml(sender As Object, e As EventArgs)
Dim dataConn As New OleDbConnection(TextBox1.Text)
Dim Path As Uri = Request.Url
Dim ServerUrl As String = Path.ToString()
ServerUrl = ServerUrl.Substring(0,Se
免责声明： 本文仅代表作者个人观点，与爱易网无关。其原创性以及文中陈述文字和内容未经本站证实，对本文以及其中全部或者部分内容、文字的真实性、完整性、及时性本站不作任何保证或承诺，请读者仅作参考，并请自行核实相关内容。
