日期:2014-05-18 浏览次数:20856 次
byte[] a ; byte[] b ; byte[] c = new byte[] { Convert.ToByte(a.Length + b.Length) }; byte[] d = new byte[c.Length + a.Length + b.Length]; int pos = 0; Buffer.BlockCopy(c, 0, d, 0, c.Length); pos += c.Length; Buffer.BlockCopy(a, 0, d, pos, a.Length); pos += a.Length; Buffer.BlockCopy(b, 0, d, pos, b.Length);
byte[] a={1,2,3}; byte[] b={5,6,7,8}; byte[] c = new byte[] { Convert.ToByte(a.Length + b.Length) }; byte[] d = a.Concat(b).Concat(c).ToArray();
------解决方案--------------------
byte[] a = { 1, 2, 3 };
byte[] b = { 5, 6, 7, 8 };
List<byte> c = new List<byte>(a);
c.AddRange(b);
return c.ToArray();
------解决方案--------------------
你觉得你的很差,其实一点也不差,在怎折腾也是拷贝过去