日期:2014-05-18  浏览次数:20795 次

问个和java对接用json做接口,json序列化和反序列的问题
客户用java做开发,sojo序列化和反序列化,得到的结果如下:"endDt":"2012-02-18 16:33:38.155",

然后我用.net做开发,这样的格式没法反序列化,错误为

  <?xml version="1.0" encoding="utf-8" ?> 
  <string xmlns="http://tempuri.org/">{"code":500,"message":"There was an error deserializing the object of type XFFW.Model.SelectiveExaminationModel. DateTime content '2012-02-18 16:33:38.155' does not start with '\\\/Date(' and end with ')\\\/' as required for JSON.","returnvalue":null}</string> 

请问碰到这样的事情怎么解决比较好

------解决方案--------------------

C# code

        /*
         * DataContractJsonSerializer在System.Runtime.Serialization.Json命名空间下,
         * .NET Framework 3.5包含在System.ServiceModel.Web.dll中,需要添加对其的引用;
         * .NET Framework 4在System.Runtime.Serialization中。     
         */

        /// <summary>
        /// JSON序列化
        /// </summary>
        public static string JsonSerializer<T>(T t)
        {
            DataContractJsonSerializer ser = new DataContractJsonSerializer(typeof(T));
            System.IO.MemoryStream ms = new System.IO.MemoryStream();
            ser.WriteObject(ms, t);
            string jsonString = System.Text.Encoding.UTF8.GetString(ms.ToArray());
            ms.Close();
            //替换Json的Date字符串
            string p = @"\\/Date\((\d+)\+\d+\)\\/";
            System.Text.RegularExpressions.MatchEvaluator matchEvaluator = new System.Text.RegularExpressions.MatchEvaluator(ConvertJsonDateToDateString);
            System.Text.RegularExpressions.Regex reg = new System.Text.RegularExpressions.Regex(p);
            jsonString = reg.Replace(jsonString, matchEvaluator);
            return jsonString;
        }

        /// <summary>
        /// JSON反序列化
        /// </summary>
        public static T JsonDeserialize<T>(string jsonString)
        {
            //将"yyyy-MM-dd HH:mm:ss"格式的字符串转为"\/Date(1294499956278+0800)\/"格式
            string p = @"\d{4}-\d{2}-\d{2}\s\d{2}:\d{2}:\d{2}";
            System.Text.RegularExpressions.MatchEvaluator matchEvaluator = new System.Text.RegularExpressions.MatchEvaluator(ConvertDateStringToJsonDate);
            System.Text.RegularExpressions.Regex reg = new System.Text.RegularExpressions.Regex(p);
            jsonString = reg.Replace(jsonString, matchEvaluator);
            DataContractJsonSerializer ser = new DataContractJsonSerializer(typeof(T));
            System.IO.MemoryStream ms = new System.IO.MemoryStream(Encoding.UTF8.GetBytes(jsonString));
            T obj = (T)ser.ReadObject(ms);
            return obj;
        }

        /// <summary>
        /// 将Json序列化的时间由/Date(1294499956278+0800)转为字符串
        /// </summary>
        private static string ConvertJsonDateToDateString(System.Text.RegularExpressions.Match m)
        {
            string result = string.Empty;
            DateTime dt = new DateTime(1970, 1, 1);
            dt = dt.AddMilliseconds(long.Parse(m.Groups[1].Value));
            dt = dt.ToLocalTime();
            result = dt.ToString("yyyy-MM-dd HH:mm:ss");
            return result;
        }

        /// <summary>
        /// 将时间字符串转为Json时间
        /// </summary>
        private static string ConvertDateStringToJsonDate(System.Text.RegularExpressions.Match m)
        {
            string result = string.Empty;
            DateTime dt = DateTime.Parse(m.Groups[0].Value);
            dt = dt.ToUniversalTime();
            TimeSpan ts = dt - DateTime.Parse("1970-01-01");
            result = string.Format("\\/Date({0}+0800)\\/", ts.TotalMilliseconds);
            return result;
        }