日期:2014-05-18  浏览次数:20901 次

求一算法,对指定字符串按照分组个数按顺序分组
例如,字符串“25482”,
如果按1组来分需要得到如下结果:
x25482
如果按2组来分得到如下结果:
x2548x2,
x254x82,
x25x482,
x2x5482
如果按3组来分需要得到如下结果:
x254x8x2,
x25x4x82,
x25x48x2,
x2x5x482,
x2x45,x82,
x2x548x2


------解决方案--------------------
//C#:
public Collection<string> Divid(string S, int Count)
{
//S: 要分的字符串;
//Count: 要分的组数
if(Count < 1 || Count > S.Length)
return null;
Result = new Collection<string>();
if(Count == 1)
{
Result.Add("x"+S);
return Result;
}
int L = S.Length;
int[] Pos = new int[Count+1]; // 'x' 插入的位置,多加一个位置以便编程
for(int i = 0; i<Count; i++)
Pos[i] = i;
Pos[Count] = L;
for(;;)
{
string R = ""
for(int i = 0; i<Count; i++)
R += "x"+S.Substring(Pos[i],Pos[i+1]);
Result.Add(R);
for(int i = 1; i<Count; i++) //检查有没有可以往后移动的
{
if(Pos[i+1] - Pos[i] >= 2)
{ //有
Pos[i] ++;
goto hesNext; //跳转到外层循环的Continue前面继续循环;

}
}
break; //没有了
hesNext: Continue;
}
return Result;
}
------解决方案--------------------
static public Collection<string> Divid(string S, int Count)
{
//S: 要分的字符串;
//Count: 要分的组数
if (Count < 1 || Count > S.Length)
return null;
Collection<string> Result = new Collection<string>();
if (Count == 1)
{
Result.Add("x" + S);
return Result;
}
int L = S.Length;
int[] Pos = new int[Count + 1]; // 'x' 插入的位置,多加一个位置以便编程
for (int i = 0; i < Count; i++)
Pos[i] = i;
Pos[Count] = L;
for (; ; )
{
string R = "";
for (int i = 0; i < Count; i++)
R += "x" + S.Substring(Pos[i], Pos[i + 1] - Pos[i]);
Result.Add(R);
for (int i = 1; i < Count; i++) //检查有没有可以往后移动的
{
if (Pos[i + 1] - Pos[i] >= 2)
{ //有
Pos[i]++;
for(int j = 1; j<i; j++) //这两行是新增加的
Pos[j] = j; //
goto hesNext; //跳转到外层循环的Continue前面继续循环;
}
}
break; //没有了
hesNext: continue;
}
return Result;
}

------解决方案--------------------
C# code
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace ConsoleApplication1
{
    class Program
    {
        static void Main(string[] args)
        {
            string s = "25482";
            int n = 2;

            var data = Enumerable.Range(1, s.Length - 1);
            IEnumerable<int[]> query = data.Select(x => new int[] { x });
            for (int i = 1; i < n; i++)
            {
                query = query.SelectMany(x => data.Select(y => x.Concat(new int[] { y }).ToArray()));
            }
            query = query
                    .Select(x => x.OrderBy(y => y).Distinct().ToArray())
                    .Where(x => x.Count() == n - 1)
                    .OrderByDescending(x => string.Join(",", x))
                    .GroupBy(x => string.Join(",", x))
                    .Select(x => x.First())
                    .Select(x => new int[] { 0 }.Concat(x).ToArray());
            foreach (var item in query)
            {
                Console.WriteLine(string.Join("", s.Select((x, i) => item.Contains(i) ? "x" + x : x.ToString())));
            }
        }
    }
}