能不能把带参数的委托的lambda 表达式改成2个参数的？
static Func<double, object> MakeAddNumber(double numberToAdd)
        {
            return x =>
            {
                try
                {
                    return x + numberToAdd;
                }
                catch (Exception ex)
                {
                    return double.NaN;
                }
            };
        }

类似改成这样：
static Func<double,double, object> MakeAddNumber(double numberToAdd)
        {
            return x = (d1,d2) =>
            {
                try
                {
                    return d1 + d2 + numberToAdd;
                }
                catch (Exception ex)
                {
                    return double.NaN;
                }
            };
        }

不太懂lamda表达式，红色的编译不通过。如果不带numberToAdd参数，能从网上找到例子，带参数的就不会了


------解决方案--------------------
static Func<double,double, object> MakeAddNumber(double numberToAdd)
        {
            return (d1,d2) =>
            {
      &nb