日期:2014-05-18 浏览次数:20795 次
using (SqlConnection con = new SqlConnection(connect.conn)) { FileStream fs = new FileStream(connect.picpath,FileMode.Open,FileAccess.Read); byte[] imagebytes = new byte[fs.Length]; BinaryReader br = new BinaryReader(fs); imagebytes = br.ReadBytes(Convert.ToInt32(fs.Length)); con.Open(); SqlCommand com = new SqlCommand("insert into employees(photo) values(@image) where employeeID="+this.textBox6.Text,con); SqlParameter image = new SqlParameter("@image",SqlDbType.Image); image.Value = imagebytes; com.Parameters.Add(image); com.ExecuteNonQuery(); }