日期:2014-05-18 浏览次数:20798 次
string source = "12ab(34cd)56e(fg78)h"; source = Regex.Replace(source, @"(\([^\)]*\))", ""); foreach (Match vMatch in Regex.Matches(source, "[a-z]")) { Console.WriteLine(vMatch.Value); }
------解决方案--------------------
(?<T1>[^\(\)]*)(?:(?=\()|(?<=\)))(?<T2>[^\(\)]*)
Class中再动态的加入自己的匹配字符
------解决方案--------------------
(?<!\([^\)]*?)[a-z]+
------解决方案--------------------
(?<Result>\w*)([\(]\w*[\)])*
string source = txtSource.Text;
MatchCollection mc = null;
Regex re = null;
re = new Regex(@"(?<Result>\w*)([\(]\w*[\)])*", RegexOptions.IgnoreCase);
mc = re.Matches(source);
string r = String.Empty;
foreach (Match m in mc)
{
r += m.Groups["Numbers"].Value;
}
txtResult.Text = r;
直接测试就可以了