类的 多个构造函数 问题
class Class1 {
int i1;
int i2;
int i3;
int i4;
int i5;
int i6;

Class1() { }

Class1(int i1, int i2) {
i1 = i1;
i2 = i2;
}

Class1(int i1, int i2, int i3, int i4) {
i1 = i1;
i2 = i2;
i3 = i3;
i4 = i4;
}

Class1(int i1, int i2, int i3, int i4, int i5, int i6) {
i1 = i1;
i2 = i2;
i3 = i3;
i4 = i4;
i5 = i5;
i6 = i6;
}
}
我记得可以调用本身的构造函数来赋值.不用这么麻烦的额!!!

------解决方案--------------------
class Class1 { 
int i1; 
int i2; 
int i3; 
int i4; 
int i5; 
int i6; 

Class1() { } 

Class1(int i1, int i2) { 
i1 = i1; 
i2 = i2; 
} 

Class1(int i1, int i2, int i3, int i4) : this(i1, i2){
i3 = i3; 
i4 = i4; 
} 

Class1(int i1, int i2, int i3, int i4, int i5, int i6): this(i1,i2,i3,i4) { 
i5 = i5; 
i6 = i6; 
} 
} 

------解决方案--------------------
C#3.0可以通过自动属性(或一般的属性)来直接赋值这样

public class C{
public int I1{get;set;}
public int I2{get;set;}
}

public class App{
C c;
public void Set(){
this.c=new C{
I1=1,I2=2
};//这种方示可代替构造函数,这样就不必象你那写多个不同的构造函数版本了.例如下面这一行
是只初始化I1的情况;
//this.c=new C{I1=1};
}
}
这种方案,的执行发生在默认构造函数调用之后;以上那种方式是简写方式,完全写法如下

C# code

//...
 public void Set(){
   this.c=new C(){I1=1,I2=2};
 }
//如果C中存在 public C(int i){this.I2=i;}那么也可以这样
 public void Set(){
  this.c=new C(22){I1=1,I2=2};
 }

------解决方案--------------------
C# code

        class Class1
        {
            private int i1;
            private int i2;
            private int i3;
            private int i4;
            private int i5;
            private int i6;

            public Class1() { }

            public Class1(int i1, int i2)
            {
                this.i1 = i1;
                this.i2 = i2;
            }

            public Class1(int i1, int i2, int i3, int i4)
                : this(i1, i2)
            {
                this.i3 = i3;
                this.i4 = i4;
            }

            public Class1(int i1, int i2, int i3, int i4, int i5, int i6)
                : this(i1, i2, i3, i4)
            {
                this.i5 = i5;
                this.i6 = i6;
            }
        }