提问个关于内容显示问题，老提示匹配的重载方法具有一些无效参数
<script   language= "C# "   runat= "server ">
void   Page_Load(Object   Src,EventArgs   E){
SqlConnection   Conn=new   SqlConnection();
Conn.ConnectionString= "server=192.168.0.26;database=xxzx;uid=sa;pwd= ' ' ";
String   strSql= "select   *   from   j_date ";
SqlCommand   Comm=new   SqlCommand(strSql,Conn);
SqlDataAdapter   da=new   SqlDataAdapter();
da.SelectCommand=Comm;
DataSet   ds=new   DataSet();
da.Fill(ds, "grade ");
DataView   dv=new   DataView(ds.Tables[ "grade "]);
string   html= "   ";
string   Name1=Request.QueryString[ "name "];
dv.RowFilter= "hzname= ' "+Name1+ " ' ";
dv.Sort= "hzid   desc ";
if   (dv.Count==0)  
  Response.Write( "没有找到！ ");
else
Response.Write(   我想在这里显示hzname的值，请问应该如何写呢);
dg.DataSource=dv;
dg.DataBind();
Conn.Close();
}
</script>

我想在这里显示hzname的值，请问应该如何写呢


------解决方案--------------------
dv.RowFilter= "hzname= ' "+Name1+ " ' ";
dv.Sort= "hzid desc ";
if (dv.Count==0)
是条件
那么hzname不就等于Name1么