日期:2014-05-19  浏览次数:21064 次

c#调用oralce函数错误(孟子等高手来,救救我)
不知道该如何调用这个函数,大哥大姐们,都来帮帮忙啊!!
函数如下,该函数有返回的是1,
具体的函数体不需要看,前两天有人告诉我使用   select   cs_csjs_zz(4102006102900000037,2007,1,1,99)   as   return_value   from   dual这种方法来调用函数,但是出现错误
ORA-14552:   cannot   perform   a   DDL,   commit   or   rollback   inside   a   query   or   DML  
ORA-06512:   at   "FINAPP.CS_CSJS_ZZ ",   line   74
ORA-14551:   cannot   perform   a   DML   operation   inside   a   query
select   cs_csjs_zz(4102006102900000037,2007,1,1,99)   as   return_value   from   dual


函数:
CREATE   OR   REPLACE   FUNCTION   CS_CSJS_ZZ
(
    an_zt_hh         IN           NUMBER,    
    an_kjnd           IN           NUMBER,    
    an_qsqj           IN           NUMBER,    
    an_jsqj           IN           NUMBER,    
    an_czyh_hh     IN           NUMBER      
)

RETURN   NUMBER   IS
    lvc_cwhdm   VARCHAR2(32);
    ln_kjzd_hh   ZZ_ZT.KJZD_HH%TYPE;
    ln_bwb_hh   ZZ_ZT.BWB_HH%TYPE;    
    li_qjjsq   INTEGER;
    CURSOR   lc_kjkm   IS                      
                  SELECT   KJKM_HH   FROM   V_ZZ_ZTKM   WHERE   JL_SC_BZ   = '0 '   AND   KJND   =   an_kjnd   AND   ZT_HH   =   an_zt_hh   ORDER   BY   kjkmdm;
    lt_kjkm   lc_kjkm%ROWTYPE;
    ln_lsjl_hh   ZZ_KJQJ.JL_HH%TYPE;
    ln_qyqj   ZZ_KJQJ.QJXH%TYPE;  
    ln_sykjqj   ZZ_KJQJ.QJXH%TYPE;
    ln_qynd   ZZ_KJQJ.KJND%TYPE;    
    ln_nmqj   ZZ_KJQJ.QJXH%TYPE;
    ln_ncqj   ZZ_KJQJ.QJXH%TYPE;
    lc_yjz_bz   ZZ_KJQJ.SFYJZ_BZ%TYPE;
    ln_jg   NUMBER;

BEGIN    
    P_ZZ_QZTQYQJ(an_zt_hh,ln_qynd,ln_qyqj,ln_sykjqj,lc_yjz_bz);    
    SELECT   MIN(QJXH),   MAX(QJXH)   INTO   ln_ncqj,   ln_nmqj   FROM   ZZ_KJQJ   WHERE   JL_SC_BZ   = '0 '   AND   QSRQ   > =   (SELECT   QYRQ   FROM   ZZ_ZT   WHERE   JL_HH=   an_zt_hh)   AND   KJND   =   an_kjnd   AND   ZT_HH   =   an_zt_hh;
   
    SELECT   DECODE(an_qsqj   -   1,0,1,an_qsqj   -   1),   KJZD_HH,   BWB_HH   INTO   ln_sykjqj,   ln_kjzd_hh,   ln_bwb_hh   FROM   ZZ_ZT   WHERE   JL_HH   =   an_zt_hh;
        li_qjjsq   :=   an_qsqj;
    LOOP
          EXIT   WHEN   li_qjjsq   >   an_jsqj;
          IF   li_qjjsq   > =   ln_ncqj   AND   li_qjjsq   <= &