日期:2014-05-19  浏览次数:20946 次

ToString("yyyy-MM-dd")的问题
编译时候报 未获得1参数 的错误.之前写是可以的,但是现在...,高手们给个提示,谢谢

------解决方案--------------------
using System;
using System.Globalization;

public class MainClass {
public static void Main(string[] args) {
DateTime dt = DateTime.Now;
String[] format = {
"d ", "D ",
"f ", "F ",
"g ", "G ",
"m ",
"r ",
"s ",
"t ", "T ",
"u ", "U ",
"y ",
"dddd, MMMM dd yyyy ",
"ddd, MMM d \ " '\ "yy ",
"dddd, MMMM dd ",
"M/yy ",
"dd-MM-yy ",
};
String date;
for (int i = 0; i < format.Length; i++) {
date = dt.ToString(format[i], DateTimeFormatInfo.InvariantInfo);
Console.WriteLine(String.Concat(format[i], " : " , date));
}

/** Output.
*
* d :08/17/2000
* D :Thursday, August 17, 2000
* f :Thursday, August 17, 2000 16:32
* F :Thursday, August 17, 2000 16:32:32
* g :08/17/2000 16:32
* G :08/17/2000 16:32:32
* m :August 17
* r :Thu, 17 Aug 2000 23:32:32 GMT
* s :2000-08-17T16:32:32
* t :16:32
* T :16:32:32
* u :2000-08-17 23:32:32Z
* U :Thursday, August 17, 2000 23:32:32
* y :August, 2000
* dddd, MMMM dd yyyy :Thursday, August 17 2000
* ddd, MMM d " ' "yy :Thu, Aug 17 '00
* dddd, MMMM dd :Thursday, August 17
* M/yy :8/00
* dd-MM-yy :17-08-00
*/
}
}

MSDN..先查查 有答案的
------解决方案--------------------
对象.ToString( "yyyy-MM-dd ")

跟踪一下出错的时候, 这个对象的字符串表示是什么? 格式不对肯定不能转换成 "yyyy-MM-dd "