public static string CmycurD(decimal num)
        {
            string str1 = "零壹贰叁肆伍陆柒捌玖";            //0-9所对应的汉字
            string str2 = "万仟佰拾亿仟佰拾万仟佰拾元角分"; //数字位所对应的汉字
            string str3 = "";    //从原num值中取出的值
            string str4 = "";    //数字的字符串形式
            string str5 = "";  //人民币大写金额形式
            int i;    //循环变量
            int j;    //num的值乘以100的字符串长度
            string ch1 = "";    //数字的汉语读法
            string ch2 = "";    //数字位的汉字读法
            int nzero = 0;  //用来计算连续的零值是几个
            int temp;            //从原num值中取出的值
        
            num = Math.Round(Math.Abs(num),2);    //将num取绝对值并四舍五入取2位小数
            str4 = ((long)(num*100)).ToString();        //将num乘100并转换成字符串形式
            j = str4.Length;      //找出最高位
            if (j > 15){return "溢出";}
            str2 = str2.Substring(15-j);   //取出对应位数的str2的值。如：200.55,j为5所以tr2=佰拾元角分
              
            //循环取出每一位需要转换的值
            for(i=0;i<j;i++)
            {
                str3 = str4.Substring(i,1);          //取出需转换的某一位的值
                temp = Convert.ToInt32(str3);      //转换为数字
                if (i != (j-3) && i != (j-7) && i != (j-11) && i != (j-15))
                {    
                    //当所取位数不为元、万、亿、万亿上的数字时
                    if (str3 == "0")
                    {
                        ch1 = "";
                        ch2 = "";
                        nzero = nzero + 1;
                    }
                    else
                    {
                        if(str3 != "0" && nzero != 0)
                        {
                            ch1 = "零" + str1.Substring(temp*1,1);
                            ch2 = str2.Substring(i,1);
                            nzero = 0;
                        }
                        else
                        {
                            ch1 = str1.Substring(temp*1,1);
                            ch2 = str2.Substring(i,1);
                            nzero = 0;
                        }
                    }
                }
                else
                {  
                    //该位是万亿，亿，万，元位等关键位
                    if (str3 != "0" && nzero != 0)
                    {
                        ch1 = "零" + str1.Substring(temp*1,1);
                        ch2 = str2.Substring(i,1);
                        nzero = 0;
                    }
                    else
                    {
                        if (str3 != "0" && nzero == 0)
                        {
                            ch1 = str1.Substring(temp*1,1);
                            ch2 = str2.Substring(i,1);
                            nzero = 0;
                        }
                        else
                        {
                            if (str3 == "0" && nzero >= 3)
                            {
                                ch1 = "";
                                ch2 = "";
                                nzero = nzero + 1;
                            }
                            else
                            {
                                if (j >= 11)
                                {
                                    ch1 = "";
                                    nzero = nzero + 1;
                                }
                                else
                                {
                                    ch1 = "";
                                    ch2 = str2.Substring(i,1);
                                    nzero = nzero + 1;
                                }
                            }
                        }
                    }
                }
                if (i == (j-11) || i == (j-3))
                {  
                    //如果该位是亿位或元位，则必须写上
                    ch2 = str2.Substring(i,1);
                }
                str5 = str5 + ch1 + ch2;
    
                if (i == j-1 && str3 == "0" )
                {    
                    //最后一位（分）为0时，加上“整”
                    str5 = str5 + '整';
                }
            }
            if (num == 0)
            {
                str5 = "零元整";
            }
            return str5;
        }