日期:2014-05-16 浏览次数:20644 次
l=len(str)
result=""
dim i
for i = 1 to l
select case mid(str,i,1)
case "<"
result=result+"<"
case ">"
result=result+">"
case chr(34)
result=result+"""
case "&"
result=result+"&"
case chr(13)
result=result+"<br>"
case chr(9)
result=result+" "
case chr(32)
'result=result+" "
if i+1<=l and i-1>0 then
if mid(str,i+1,1)=chr(32) or mid(str,i+1,1)=chr(9) or mid(str,i-1,1)=chr(32) or mid(str,i-1,1)=chr(9) then
result=result+" "
else
result=result+" "
end if
else
result=result+" "
end if
case else
result=result+mid(str,i,1)
end select
next
if err.number<>0 then err.clear
htmlencode=result
end function
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