日期:2014-05-17  浏览次数:20711 次

为什么我的代码不能进行跳转呢
<html>
<head>

<meta http-equiv="Content-Type" content="text/html; charset=gb2312">
<title>正在进入</title>
</head>
<body>
<form name=loading> 
 <p align=center> <font color="#0066ff" size="2">正在进入,请稍等</font><font color="#0066ff" size="2" face="Arial">...</font>
  <a href="http://www.jxy120.com">高血压吃什么好</a>
  <input type=text name=chart size=46 style="font-family:Arial; font-weight:bolder; color:#0066ff; background-color:#fef4d9; padding:0px; border-style:none;"> 
  
  <input type=text name=percent size=47 style="color:#0066ff; text-align:center; border-width:medium; border-style:none;"> 
  <script>  
var bar=0  
var line="||"  
var amount="||"  
count()  
function count(){  
bar=bar+2  
amount =amount + line  
document.loading.chart.value=amount  
document.loading.percent.value=bar+"%"  
if (bar<99)  
{setTimeout("count()",100);}  
else  
{window.location = "http://www.jxy120.com";}  
}</script> 
 </p> 
</form> 
<p align="center"> 如果您的浏览器不支持跳转,<a style="text-decoration: none" href="http://www.jxy120.com"><font color="#FF0000">请点这里</font></a>.</p>
</body>
</html>