急急急！struts2报404错误！所有分都送上！
现在在做一个项目，配置环境：tomcat6.0.35 +　JDK1.6.0_30 + struts2.3.1.2 + mysql5.0
但是form提交的时候，报404错误.
进入index.jsp提交后，报错“HTTP Status 404 - /huazhaosoft/manager.do”
type Status report

message /huazhaosoft/manager.do

description The requested resource (/huazhaosoft/manager.do) is not available.



index.jsp
<form name="form1" method="post" action="manager.do?action=login">

web.xml

<?xml version="1.0" encoding="UTF-8"?>  
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"  
  xmlns="http://java.sun.com/xml/ns/javaee" 
  xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"  
  xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"  
  id="WebApp_ID" version="3.0">  
<display-name>SSH</display-name>  
<welcome-file-list>  
  <welcome-file>index.jsp</welcome-file>  
</welcome-file-list>  
   
<filter>  
  <filter-name>struts2</filter-name>  
  <filter-class>org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter</filter-class>  
</filter>  
   
<filter-mapping>  
  <filter-name>struts2</filter-name>  
  <url-pattern>/*</url-pattern>  
</filter-mapping>  
</web-app> 


struts.xml
<?xml version="1.0" encoding="UTF-8" ?>  
<!DOCTYPE struts PUBLIC  
  "-//Apache Software Foundation//DTD Struts Configuration 2.0//EN"  
  "http://struts.apache.org/dtds/struts-2.0.dtd">  
<struts>  
  <constant name="struts.action.extension" value="do" />
  <constant name="struts.devMode" value="true" />
  <constant name="struts.enable.DynamicMethodInvocation" value="false" />
  <package name="package" extends="struts-default" namespace="/huazhaosoft">  
  <action name="managerForm" path="/manager" scope="request" type="com.action.Manager" validate="true">  
  <forward name="managerLoginok" path="/welcome.jsp" />
  <forward name="error" path="/welcome.jsp" />
  </action>  
  </package>  
</struts> 


manager.java
package com.action;

import org.apache.struts.action.*;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import com.actionForm.ManagerForm;
import com.dao.ManagerDAO;
import javax.servlet.http.HttpSession;

public class Manager extends Action {
private ManagerDAO managerDAO = null;

public Manager() {
this.managerDAO = new ManagerDAO();
}

public ActionForward execute(ActionMapping mapping, ActionForm form,
HttpServletRequest request, HttpServletResponse response) {
String action = request.getParameter("action");
System.out.println("获取的查询字符串：" + action);
if (action == null || "".equals(action)) {
return mapping.findForward("error");