ERROR org.apache.struts2.dispatcher.Dispatcher Could not find action or result解决方法
日期：2014-05-17 浏览次数：20669 次
ERROR org.apache.struts2.dispatcher.Dispatcher Could not find action or result
2011-09-19 17:03:49,348 ERROR (org.apache.struts2.dispatcher.Dispatcher:515) - Could not find action or result
There is no Action mapped for namespace / and action name login. - [unknown location]
at com.opensymphony.xwork2.DefaultActionProxy.prepare(DefaultActionProxy.java:186)
at org.apache.struts2.impl.StrutsActionProxyFactory.createActionProxy(StrutsActionProxyFactory.java:41)
at org.apache.struts2.dispatcher.Dispatcher.serviceAction(Dispatcher.java:497)
at org.apache.struts2.dispatcher.FilterDispatcher.doFilter(FilterDispatcher.java:421)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:235)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127)
at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102)
at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:298)
at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:852)
at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:588)
at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:489)
at java.lang.Thread.run(Unknown Source)
下面是struts2的配置文件
<struts>
<package name="default" extends="struts-default" >
<action name="login.action" class="com.test.web.action.LoginAction">
<result name="input">/login.jsp</result>
<result name="success">/WEB-INF/jsp/list.jsp</result>
</action>
</package>
</struts>
下面是web的配置文件
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/classes/applicationContext.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<filter>
<filter-name>struts2</filter-name>
<filter-class>org.apache.struts2.dispatcher.FilterDispatcher</filter-class>
</filter>
<filter-mapping>
<filter-name>struts2</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
下面是登录的JSP
<body>
<center><h3>请输入用户名和密码来登陆</h3>
<s:form action="login.action" method="POST">
<s:textfield name="username" label="用户名"/>
<s:textfield name="password" label="密码"/>
<s:submit value="登陆"/>
</s:form>
</body>
很郁闷就是找不到错出现在哪里，有哪位大虾能看出来
------解决方案--------------------
<result name="input">/login.jsp</result>
<result name="success">/jsp/l
2011-09-19 17:03:49,348 ERROR (org.apache.struts2.dispatcher.Dispatcher:515) - Could not find action or result
There is no Action mapped for namespace / and action name login. - [unknown location]
at com.opensymphony.xwork2.DefaultActionProxy.prepare(DefaultActionProxy.java:186)
at org.apache.struts2.impl.StrutsActionProxyFactory.createActionProxy(StrutsActionProxyFactory.java:41)
at org.apache.struts2.dispatcher.Dispatcher.serviceAction(Dispatcher.java:497)
at org.apache.struts2.dispatcher.FilterDispatcher.doFilter(FilterDispatcher.java:421)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:235)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127)
at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102)
at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:298)
at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:852)
at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:588)
at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:489)
at java.lang.Thread.run(Unknown Source)
下面是struts2的配置文件
<struts>
<package name="default" extends="struts-default" >
<action name="login.action" class="com.test.web.action.LoginAction">
<result name="input">/login.jsp</result>
<result name="success">/WEB-INF/jsp/list.jsp</result>
</action>
</package>
</struts>
下面是web的配置文件
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/classes/applicationContext.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<filter>
<filter-name>struts2</filter-name>
<filter-class>org.apache.struts2.dispatcher.FilterDispatcher</filter-class>
</filter>
<filter-mapping>
<filter-name>struts2</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
下面是登录的JSP
<body>
<center><h3>请输入用户名和密码来登陆</h3>
<s:form action="login.action" method="POST">
<s:textfield name="username" label="用户名"/>
<s:textfield name="password" label="密码"/>
<s:submit value="登陆"/>
</s:form>
</body>
很郁闷就是找不到错出现在哪里，有哪位大虾能看出来
------解决方案--------------------
<result name="input">/login.jsp</result>
<result name="success">/jsp/l
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