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<div id="view" onmouseover="showDiv(1)" onmouseout="showDiv(0)" onmousemove="mouseMove(event)">查看</div>

<div id="area" style="display:none;">这里的数据用ajax去请求过来</div>



<script language="javascript" type="text/javascript">

        function showDiv(open)

        {

            document.getElementById("area").style.display=open?"":"none";

        }

        

        function mouseMove(e)

        {

            var o = document.getElementById("area");

            o.style.left = mousePos(e).x-170;

            o.style.top = mousePos(e).y;

        }

        function mousePos(e)

        {

            var x,y;

            var e = e
------解决方案--------------------
window.event;

            return {

                x:e.clientX+document.body.scrollLeft+document.documentElement.scrollLeft,

                y:e.clientY+document.body.scrollTop+document.documentElement.scrollTop

            };

        };

</script>

我用了你这人个，可以用，但我想鼠标能点到悬浮窗里面的东西啊，这要怎么改。

你看下那几个事件啊，把onmouseout="showDiv(0)"