servlet 问题
先说一下自己的配置啊!!!
C:\Program Files\Apache Software Foundation\Tomcat 6.0\conf\Catalina\localhost 目录下配置webApp.xml 内容为 <Context path= "/webApp " docBase= "F:\webApp " reloadable= "true ">
</Context>
在F:\webApp目录下建有src ,WEB-INF目录 WEB-INF目录下有classes目录和web.xml文件web.xml内容为
<?xml version= "1.0 " encoding= "gb2312 "?>
<!--
Licensed to the Apache Software Foundation (ASF) under one or more
contributor license agreements. See the NOTICE file distributed with
this work for additional information regarding copyright ownership.
The ASF licenses this file to You under the Apache License, Version 2.0
(the "License "); you may not use this file except in compliance with
the License. You may obtain a copy of the License at
http://www.apache.org/licenses/LICENSE-2.0
Unless required by applicable law or agreed to in writing, software
distributed under the License is distributed on an "AS IS " BASIS,
WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
See the License for the specific language governing permissions and
limitations under the License.
-->
<web-app xmlns= "http://java.sun.com/xml/ns/javaee "
xmlns:xsi= "http://www.w3.org/2001/XMLSchema-instance "
xsi:schemaLocation= "http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd "
version= "2.5 ">
<display-name> Welcome to Tomcat </display-name>
<description>
Welcome to Tomcat
</description>
<servlet>
<servlet-name> CreateDBServlet </servlet-name>
<servlet-class> CreateDBServlet </servlet-class>
<init-param>
<param-name> driverClass </param-name>
<param-value> com.mysql.jdbc.Driver </param-value>
</init-param>
<init-param>
<param-name> urll </param-name>
<param-value> jdbc:mysql://localhost:3306/mysql </param-value>
</init-param>
<init-param>
<param-name> user </param-name>
<param-value> root </param-value>
</init-param>
<init-param>
<param-name> password </param-name>
<param-value> 472958355 </param-value>
</init-param>
</servlet>