JAVABEAN中写数据库查询语句的问题
环境access+tomcat
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access中查询语句:
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select * from products where category= 'computer '
或:
select * from products where category= "computer "
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javabean中语句:
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ResultSet rst=stmt.executeQuery( "select * from Products where category= ' "+categoryId+ " ' ");
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access中查询语句:
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select * from products where name like '*1* ';
或
select * from products where name like "*1* ";
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javabean中语句:
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ResultSet rst=stmt.executeQuery( "select * from Products where name like '% "+nameId+ "% ' ");
谁能给我解释下: '% "+nameId+ "% ' 这段文字。。。
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具体文件如下:
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public class ProductBean
{
private Connection con;
//构造方法,获得数据库的连接。
public ProductBean(){
this.con=DataBaseConnection.getConnection();
}
/按照商品的类别查找商品,
public Collection getProductByCategory(String categoryId)throws Exception
{
Statement stmt=con.createStatement();
ResultSet rst=stmt.executeQuery( "select * from Products where category= ' "+categoryId+ " ' ");
Collection ret=new ArrayList();
while(rst.next())
{
Product temp=new Product();
temp.setProductId(rst.getString( "productid "));
temp.setCategoryId(rst.getString( "category "));
temp.setName(rst.getString( "name "));
temp.setDescription(rst.getString( "descn "));
temp.setProducer(rst.getString( "producer "));
temp.setPrice(rst.getString( "price "));
ret.add(temp);
}
con.close();
return ret;
}
//按名称匹配查询。
public Collection getProductByName(String nameId)throws Exception
{
Statement stmt=con.createStatement();
ResultSet rst=stmt.executeQuery( "select * from Products where name like '% "+nameId+ "% ' ");
Collection ret=new ArrayList();
while(rst.next())
{
Product temp=new Product();
temp.setProductId(rst.getString( "productid "));
temp.setCategoryId(rst.getString( "category "));
temp.setName(rst.getString( "name "));
temp.setDescription(rst.getString( "descn "));
temp.setProducer(rst.getString( "producer "));
temp.setPrice(rst.getString( "price "));
ret.add(temp);
}
con.close();
return ret;
}
}
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------解决方案--------------------System.out.println( "select * from Products where n