日期:2014-05-18  浏览次数:20783 次

用form.action进行页面跳转问题
跳转不起作用,点击编辑字段按钮,还是提交到本页面。请帮忙看代码如下:

<%@   page   contentType= "text/html;   charset=utf-8 "   language= "java "%>
<%@   page   import= "java.sql.* "%>
<html>
<head>
<script   type= "text/javascript "   src= "/html/ytx/standard.js "   > </script>
<link   href= "/html/ytx/wstyle.css "   rel= "stylesheet "   type= "text/css ">
<script>

function   columnclick(form){
                form.aciton   =   "zYTXChartColumn.jsp ";
form.submit();
}

</script>
</head>
<body>

<br>
<form   name= "form1 "   method= "post "   action= " ">
  <table   align= "center "   cellspacing= "1 "   width= "100% "   class= "normaltable "   border= "1 ">

<%
out.println( " <td   class= 'ytxtd '     width= '8% '   align=\ "center\ "   > <input   type= 'button '   name= 'button '   value= '编辑字段 '   onclick=\ "columnclick(form1)\ "> </td>   ");

%>

</table>

</form>
</body>
</html>


------解决方案--------------------
form.aciton = "zYTXChartColumn.jsp ";
这一句出错了,是action而不是aciton......
------解决方案--------------------
hehe. need more careful
------解决方案--------------------
呵呵 仔细点 我刚学那会也老出这种问题