jsp、struts页面跳转有关问题
日期：2014-05-18 浏览次数：20621 次
jsp、struts页面跳转问题
登录与注册界面：1.先按下 "登录 ",报 "no user ",再按下 "注册 ",页面路径错误
2.直接按下 "注册 ",没有任何问题
我写的代码如下：
1.jsp
<head> <title> <bean:message key= "title "/> </title> </head>
<script language= "javascript ">
function login()
{
document.LoginForm.submit();
}
function register()
{
window.location= "register.jsp ";
}
</script>
<body background= "images/bg.gif ">
<html:form action= "/LoginAction " focus= "userName ">
<table bgcolor= "aaff " width= "100% " >
<tr>
<td>
<bean:message key= "userName "/> : <html:text property= "userName " name= "userName " value= " " size= "10 "/>  
<bean:message key= "password "/> : <html:text property= "password " name= "password " value= " " size= "10 "/>
<logic:messagesPresent message= "failLogin ">
<html:errors property= "loginFail "/>
</logic:messagesPresent>
<input type= "button " onclick= "login() " value= " <bean:message key= "submit "/> " />  
<input type= "reset " value= " <bean:message key= "reset "/> "/>  
<input type= "button " onclick= "register() " value= " <bean:message key= "register "/> "/>
</td>
</tr>
</table>
</html:form>
</body>
2.java--Action
public ActionForward execute(ActionMapping mapping,ActionForm actionForm,
HttpServletRequest request,HttpServletResponse response)
{
boolean bool=false;
ActionErrors errors=new ActionErrors();
ActionForward actionForward=new ActionForward();
LoginForm form=(LoginForm)actionF
登录与注册界面：1.先按下 "登录 ",报 "no user ",再按下 "注册 ",页面路径错误
2.直接按下 "注册 ",没有任何问题
我写的代码如下：
1.jsp
<head> <title> <bean:message key= "title "/> </title> </head>
<script language= "javascript ">
function login()
{
document.LoginForm.submit();
}
function register()
{
window.location= "register.jsp ";
}
</script>
<body background= "images/bg.gif ">
<html:form action= "/LoginAction " focus= "userName ">
<table bgcolor= "aaff " width= "100% " >
<tr>
<td>
<bean:message key= "userName "/> : <html:text property= "userName " name= "userName " value= " " size= "10 "/>  
<bean:message key= "password "/> : <html:text property= "password " name= "password " value= " " size= "10 "/>
<logic:messagesPresent message= "failLogin ">
<html:errors property= "loginFail "/>
</logic:messagesPresent>
<input type= "button " onclick= "login() " value= " <bean:message key= "submit "/> " />  
<input type= "reset " value= " <bean:message key= "reset "/> "/>  
<input type= "button " onclick= "register() " value= " <bean:message key= "register "/> "/>
</td>
</tr>
</table>
</html:form>
</body>
2.java--Action
public ActionForward execute(ActionMapping mapping,ActionForm actionForm,
HttpServletRequest request,HttpServletResponse response)
{
boolean bool=false;
ActionErrors errors=new ActionErrors();
ActionForward actionForward=new ActionForward();
LoginForm form=(LoginForm)actionF
免责声明： 本文仅代表作者个人观点，与爱易网无关。其原创性以及文中陈述文字和内容未经本站证实，对本文以及其中全部或者部分内容、文字的真实性、完整性、及时性本站不作任何保证或承诺，请读者仅作参考，并请自行核实相关内容。
