struts2的转发页面异常(404)
日期：2014-05-19 浏览次数：20730 次
struts2的转发页面错误(404)
测试struts2中的Action是如何通过ActionContext访问Servlet API的,实例是模仿登录业务逻辑,分别把登录用户名保存在application和session中,然后从jsp页面中读取信息
可是我页面跳转的时候报404找不到页面的错误,仔细检查了struts.xml,好像也没有什么错误啊!
登录业务逻辑:LoginAction.java
package com;
import java.util.Map;
import com.opensymphony.xwork2.ActionSupport;
import com.opensymphony.xwork2.ActionContext;
@SuppressWarnings("serial")
public class LoginAction extends ActionSupport{
private String name;
private String pwd;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getPwd() {
return pwd;
}
public void setPwd(String pwd) {
this.pwd = pwd;
}
@SuppressWarnings("unchecked")
public String checkLogin(){
ActionContext ac = ActionContext.getContext();
@SuppressWarnings({ "unused", "rawtypes" })
Map app = ac.getApplication();
ac.getSession().put("login", this.name);
ac.getApplication().put("login", this.name);
return SUCCESS;
}
}
web.xml页面
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<!-- 定义Struts2的FilterDispathcer的Filter -->
<filter>
<filter-name>struts2</filter-name>
<filter-class>org.apache.struts2.dispatcher.FilterDispatcher</filter-class>
</filter>
<!-- FilterDispatcher用来初始化struts2并且处理所有的WEB请求。 -->
<filter-mapping>
<filter-name>struts2</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>
struts.xml
<?xml version="1.0" encoding="gb2312"?>
<!DOCTYPE struts PUBLIC
"-//Apache Software Foundation//DTD Struts Configuration 2.0//EN"
"http://struts.apache.org/dtds/struts-2.0.dtd">
<struts>
<include file="struts-default"/>
<package name="default" extends="struts_default" namespace="/login">
<action name="loginAction" class="com.LoginAction" method="checkLogin">
<result>/index.jsp</result>
</action>
</package>
</struts>
login.jsp
<%@ page language="java" contentType="text/html; charset=gb2312"
pageEncoding="gb2312"%>
<%@ taglib uri="/struts-tags" prefix="s" %>
<html>
<head>
<title>session or application</title>
</head>
<body style="background-image:url('images/bg-0414.gif')">
<center>
<br><h2>用户登录</h2>
<s:form action="loginAction" method="post" namespace="/login">
<s:textfield name="name" label="登录名称" size="15"/>
<s:password name="pw
测试struts2中的Action是如何通过ActionContext访问Servlet API的,实例是模仿登录业务逻辑,分别把登录用户名保存在application和session中,然后从jsp页面中读取信息
可是我页面跳转的时候报404找不到页面的错误,仔细检查了struts.xml,好像也没有什么错误啊!
登录业务逻辑:LoginAction.java
package com;
import java.util.Map;
import com.opensymphony.xwork2.ActionSupport;
import com.opensymphony.xwork2.ActionContext;
@SuppressWarnings("serial")
public class LoginAction extends ActionSupport{
private String name;
private String pwd;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getPwd() {
return pwd;
}
public void setPwd(String pwd) {
this.pwd = pwd;
}
@SuppressWarnings("unchecked")
public String checkLogin(){
ActionContext ac = ActionContext.getContext();
@SuppressWarnings({ "unused", "rawtypes" })
Map app = ac.getApplication();
ac.getSession().put("login", this.name);
ac.getApplication().put("login", this.name);
return SUCCESS;
}
}
web.xml页面
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<!-- 定义Struts2的FilterDispathcer的Filter -->
<filter>
<filter-name>struts2</filter-name>
<filter-class>org.apache.struts2.dispatcher.FilterDispatcher</filter-class>
</filter>
<!-- FilterDispatcher用来初始化struts2并且处理所有的WEB请求。 -->
<filter-mapping>
<filter-name>struts2</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>
struts.xml
<?xml version="1.0" encoding="gb2312"?>
<!DOCTYPE struts PUBLIC
"-//Apache Software Foundation//DTD Struts Configuration 2.0//EN"
"http://struts.apache.org/dtds/struts-2.0.dtd">
<struts>
<include file="struts-default"/>
<package name="default" extends="struts_default" namespace="/login">
<action name="loginAction" class="com.LoginAction" method="checkLogin">
<result>/index.jsp</result>
</action>
</package>
</struts>
login.jsp
<%@ page language="java" contentType="text/html; charset=gb2312"
pageEncoding="gb2312"%>
<%@ taglib uri="/struts-tags" prefix="s" %>
<html>
<head>
<title>session or application</title>
</head>
<body style="background-image:url('images/bg-0414.gif')">
<center>
<br><h2>用户登录</h2>
<s:form action="loginAction" method="post" namespace="/login">
<s:textfield name="name" label="登录名称" size="15"/>
<s:password name="pw
免责声明： 本文仅代表作者个人观点，与爱易网无关。其原创性以及文中陈述文字和内容未经本站证实，对本文以及其中全部或者部分内容、文字的真实性、完整性、及时性本站不作任何保证或承诺，请读者仅作参考，并请自行核实相关内容。
