HTTP Status 500 是什么错误?
HTTP Status 500 -
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type Exception report
message
description
The server encountered an internal error () that prevented it from fulfilling this request.exception
org.apache.jasper.JasperException: An exception occurred processing JSP page /login_in.jsp at line 10
7: <%@include file="inc/mhead.inc"%>
8: <%
9: String sid = request.getParameter("id");
10: int id = Integer.parseInt(sid);
11: String sql = "select * from memberslist where id=" + id + "";
12: Sql.dbconnection();
13: Sql.dbhandle(sql, 1);
Stacktrace:
org.apache.jasper.servlet.JspServletWrapper.handle
JspException(JspServletWrapper.java:524)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:435)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:320)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266)
javax.servlet.http.HttpServlet.service(HttpServlet.java:803)
root cause
java.lang.NumberFormatException: null java.lang.Integer.parseInt(Integer.java:415)
java.lang.Integer.parseInt(Integer.java:497)
org.apache.jsp.login_005fin_jsp._jspService(login_005fin_jsp.java:140)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
javax.servlet.http.HttpServlet.service(HttpServlet.java:803)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:393)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:320)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266)
javax.servlet.http.HttpServlet.service(HttpServlet.java:803)
note The full stack trace of the root cause is available in the Apache Tomcat/6.0.13 logs.
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Apache Tomcat/6.0.13
各位大侠如何解救啊?
------解决方案--------------------
后台处理错误了
org.apache.jasper.JasperException:
An exception occurred processing JSP page /login_in.jsp at line 10
9: String sid = request.getParameter("id");
10: int id = Integer.parseInt(sid);
java.lang.NumberFormatException: null
java.lang.Integer.parseInt(Integer.java:415)
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说明你的输入参数id可能为空或者不是数字
------解决方案--------------------500 是服务器严重错误。看你的异常好像这个
NumberFormatException数字格式化的时候异常了。
9: String sid = request.getParameter("id");
10: int id = Integer.parseInt(sid);
你的sid没有得到值,得到NULL,所以在转换成int的时候就异常了。
------解决方案--------------------向当前这个页面跳转的URL后面缺少id参数和值。
我的异常网推荐解决方案:An exception occurred processing JSP page,http://www.aiyiweb.com/j2se/33144.html
我的异常网推荐解决方案:The server encountered an internal error () that prevented it from fulfilling this request.,http://www.myexcept