日期:2014-05-20  浏览次数:20779 次

Spring 的java mail的问题,如何伪装发件人?
帮公司开发了一套360度调查系统,当中用到了Java mail发送邮件给用户。
  这里发现了一个问题,因为我用统一的SMTP服务器发送邮件,而我想每次发送邮件的时候发件人地址都不同,但是我发现无法通过验证,总是报错说发件人验证失败。
  我贴一段我自己写的简易代码,我想问一下如何伪装发件人,如何设置成不用验证发件人的,谢谢
 
Java code
package mail;

import org.springframework.mail.javamail.JavaMailSenderImpl;

import org.springframework.mail.javamail.MimeMessageHelper;

import javax.mail.internet.MimeMessage;

import java.util.Properties;

import java.util.Date;

/**

* @author levinhou

*/

public class SendMail {

//邮件发送器

public static String Sender(String subject, String msg, String sendTo, String fromMail, String user, String pw, String fromName, String protocol, String host, String port){

try{

final String username = user;

final String pass = pw;

//需要认证

Properties props = new Properties();

props.put("mail.smtp.host", host);

props.put("mail.smtp.auth", "true");

props.put("mail.transport.protocol", protocol);

props.put("mail.from", fromMail);

//创建发送器

JavaMailSenderImpl sender = new JavaMailSenderImpl();

sender.setHost(host);

sender.setUsername(username);

sender.setPassword(pass);

//创建消息

MimeMessage message = sender.createMimeMessage();

message.addHeader("X-Mailer", "Java Mailer");

MimeMessageHelper helper = new MimeMessageHelper(message);

helper.setTo(sendTo);

helper.setFrom(fromMail, fromName);

helper.setSubject(subject);

helper.setText(msg);

helper.setSentDate(new Date());

//开始发送

sender.setJavaMailProperties(props);

sender.send(message);

}catch(Exception e){

System.out.println("Error:" + e);

return "Failure";

}

return "Success";

}

//测试

public static void main(String args[])throws Exception

{

String subject = "测试邮件";//标题

String sendTo = "windhall@126.com";//接收者邮件

String fromMail = "123@126.com";//发送者邮件

String user = "windhall";//发送者用户

String pw = "xxxxxxxx";//发送者邮件密码

String fromName = "Chen";//发送者名字

String protocol = "smtp";//协议

String host = "smtp.126.com";//发送主机

String port = "25";//端口

String msg = "简单邮件发送。";//发送内容

String ret = Sender(subject, msg, sendTo, fromMail, user, pw, fromName, protocol, host, port);

System.out.println("邮件发送结果:" + ret);

}

}


代码里的收件人我乱填了一个,就无法通过验证~

------解决方案--------------------
你写复杂了,以下是我的代码,发送人可任意填写.
Java code
import java.net.InetAddress;
import java.util.Properties;

import javax.mail.Message;
import javax.mail.Session;
import javax.mail.Transport;
import javax.mail.internet.InternetAddress;
import javax.mail.internet.MimeMessage;

public class SendMail {
    /**
     * 发送邮件测试
     */
    public static void main(String[] args) {
        try {
            // Get system properties
            Properties props = System.getProperties();
    
            // 设置smtp邮件服务器
            props.put("mail.smtp.host", "192.168.0.61");
            props.setProperty("mail.smtp.port", "25");
            props.put("mail.smtp.auth", false);
            
            // 取得连接
            Session session = Session.getDefaultInstance(props, null);
            Transport transport = session.getTransport("smtp");
            transport.connect();
    
            // 邮件定义
            MimeMessage mail = new MimeMessage(session);
            
            mail.addRecipient(Message.RecipientType.TO, new InternetAddress("To@test.com"));
            mail.setSubject("邮件标题……");
            mail.setText("邮件正文……");
            mail.setFrom(new InternetAddress("from@test.com"));
            transport.sendMessage(mail, mail.getAllRecipients());
               transport.close();
            
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}