怎样拿到Matcher m=pattern.matcher(str);里分组的值
String str ="${time}";
String req="\\$\\{([a-z]{4})\\}";
Pattern pattern=Pattern.compile(req);
Matcher m=pattern.matcher(str);
String c = m.group(1)
boolean s=m.find();
System.out.println(c);
怎样拿到Matcher m=pattern.matcher(str);里分组的值 也就是字符串里time的值 String c = m.group(1)拿不到 报
java.lang.IllegalStateException: No match found错
------解决方案--------------------
要先调用m.find()后才能从group里面取值,你的程序正好写反了,你是先group,然后才调用find的
Java code
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Test {
public static void main(String[] args) {
String str ="${time}";
String req="\\$\\{([a-z]{4})\\}";
Pattern pattern=Pattern.compile(req);
Matcher m=pattern.matcher(str);
boolean s=m.find();
if (s) {
String c = m.group(1);
System.out.println(c);
} else {
System.out.println("Not found.");
}
}
}