struts2 测试
package sunyang.vote.dao.impl;

import java.util.List;

import org.hibernate.Session;
import org.springframework.orm.hibernate3.support.HibernateDaoSupport;

import sunyang.vote.dao.AdminDao;
import sunyang.vote.domain.Admin;

public class AdminDaoImpl extends HibernateDaoSupport implements AdminDao {

@SuppressWarnings("unchecked")
public List<Admin> findAll() {
return (List<Admin>) getHibernateTemplate().find("from Admin");
}

public void addAdmin(Admin admin) {
getHibernateTemplate().save(admin);
}

@SuppressWarnings("unchecked")
public Admin findAdmin(String name, String password) {
String[] param = new String[] { name, password };
String sql = "from Admin as admin where admin.name=? and admin.password=?";
List<Admin> list = getHibernateTemplate().find(sql, param);
if (list != null && list.size() > 0)
return list.get(0);
else
return null;
}

public void changepwd(Admin admin) {
getHibernateTemplate().update("password", admin);
}

public void updatelogintime(Admin admin) {
getHibernateTemplate().update("logintime", admin);
}

@SuppressWarnings("unchecked")
public Admin findNameById(Integer adminId) {
String sql = "from Admin as admin where admin.adminId=?";
List<Admin> list = getHibernateTemplate().find(sql, adminId);
return list.get(0);
}

@SuppressWarnings("unchecked")
public Admin findAdminByName(String name) {
String sql = "from Admin as admin where admin.name=?";
List<Admin> list = getHibernateTemplate().find(sql, name);
if (list != null && list.size() > 0)
return list.get(0);
else
return null;
}

public static void main(String[] s){
AdminDaoImpl dao=new AdminDaoImpl();
Admin a=dao.findNameById(new Integer(4));
List<Admin> list=dao.findAll();
System.out.println(a.getName());
}

}

我想用了main函数测试这个持久化层的类是不是这样子写的呀，怎么老是不行呀，希望高手帮下手


------解决方案--------------------
from Admin as admin where admin.adminId=?

有可能是你的字段名写错了？ adminId-- admin_id？