Hibernate中如何执行不等于查询？
使用getHibernateTemplate()查询数据库:

Java code

this.getHibernateTemplate().find("from mytable where id='0001'");

上面的代码可以正常执行，然后执行不等于查询

Java code

this.getHibernateTemplate().find("from mytable where id<>'0002'");

这次产生了错误，错误如下：
org.springframework.orm.hibernate3.HibernateQueryE xception: unexpected token: <> near line 1, column 41 [from mytable id <>'0002']; nested exception is org.hibernate.hql.ast.QuerySyntaxException: unexpected token: <> near line 1, column 41 [from mytable where id <>'0002']

然后将'<>'改为'!=' 还是产生错误:
org.springframework.orm.hibernate3.HibernateQueryE xception: unexpected token: != near line 1, column 41 [from mytable id !='0002']; nested exception is org.hibernate.hql.ast.QuerySyntaxException: unexpected token: != near line 1, column 41 [from mytable where id !='0002']

为什么会产生上面的错误，如何才能使用不等于查询？


------解决方案--------------------
from mytable id <>'0002' ？？
where怎么没了