【求助】使用jaxb如何序列化 List对象啊

List<Book> books =new ArrayList<Book>();

Book book=new Book();

book.setName="书名1";

book.setContent="内容1";



Book book2=new Book();

book2.setName="书名2";

book2.setContent="内容2";

books.add(book);

books.add(book2);

请问使用jaxb 如何实现 list 和xml之间的相互转化？？
非常感谢
------解决方案--------------------
book类

private String name;

	private String content;



	public String getName() {

		return name;

	}



	public void setName(String name) {

		this.name = name;

	}



	public String getContent() {

		return content;

	}



	public void setContent(String content) {

		this.content = content;

	}

生成xml

List<Book> books =new ArrayList<Book>();

		Book book=new Book();

		book.setName("书名1");

		book.setContent("内容1");



		Book book2=new Book();

		book2.setName("书名2");

		book2.setContent("内容2");

		books.add(book);

		books.add(book2);

		

		JAXBContext context = JAXBContext.newInstance(Book.class);

		

		Marshaller marshaller = context.createMarshaller();

		marshaller.setProperty(Marshaller.JAXB_ENCODING, "GBK");

		marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, false);

		marshaller.setProperty(Marshaller.JAXB_FRAGMENT, true);



		String ns = "book";

		XMLOutputFactory output = XMLOutputFactory.newInstance();

		output.setProperty(XMLOutputFactory.IS_REPAIRING_NAMESPACES, true);

		

		

		File file = new File("d:/jaxbtest.txt");

		OutputStream out = new FileOutputStream(file);

		XMLStreamWriter writer = output.createXMLStreamWriter(out,"UTF-8");

		writer.writeStartDocument();

		writer.setDefaultNamespace(ns);

		writer.writeStartElement(ns,"booklist");

		

		int i = 0;



		for(Iterator it = books.iterator();it.hasNext();){

			QName qname = new QName("book" + String.valueOf(i));

			i++;

			Book bk = (Book)it.next();

			JAXBElement<Book> bookElement = new JAXBElement<Book>(qname,Book.class,bk);

			marshaller.marshal(bookElement, writer);

			writer.flush();

		}

		writer.writeEndElement();

		writer.writeEndDocument();

		writer.flush();

生成结果如下：
<?xml version='1.0' encoding='UTF-8'?>
<booklist xmlns="book">
<book0 xmlns="">
<content>内容1</content>
<name>书名1</name>
</book0>
<book1 xmlns="">
<content>内容2</content>
<name>书名2</name>
</book1>
</booklist>
------解决方案--------------------
Book.java

@XmlType(propOrder={"name","content"})

@XmlRootElement(name="book")

public class Book {

    private String name;

    private String content;



    @XmlElement

    public final String getContent() {

        return content;