String regex = "/(news|finance)/.*[?&]from=ucweb([&#].*|$)";
    System.out.println("/news/abroad/zhuanti?nid=122334&from=ucweb&foo=sthelse".matches(regex));
    System.out.println("/news/?from=ucweb&foo=sthelse".matches(regex));
    System.out.println("/news/abroad/zhuanti?nid=122334&from=ucweb".matches(regex));
    System.out.println("/news/abroad/zhuanti?nid=122334&from=ucweb#anchor".matches(regex));
    System.out.println("/news/abroad/zhuanti?nid=122334&xfrom=ucwebtt".matches(regex));
    System.out.println("/news/abroad/zhuanti?nid=122334&xfrom=ucweb".matches(regex));
    System.out.println("/news/abroad/zhuanti?nid=122334&from=ucwebtt".matches(regex));
    System.out.println("/news/abroad/zhuanti?xfrom=ucweb".matches(regex));
    System.out.println("/news/abroad/zhuanti?from=ucwebtt".matches(regex));

------解决方案--------------------

是匹配(/news/|/finace/)&from=ucweb，即/news或/finace后面紧跟/&from=cuweb，还是说以/news/或/finace/开头，中间可以出现任意abroad/zhuanti，然后跟着&from=cuweb，随后任意，即&foo=sthelse可有可无

have a try
Java code
String regex = "/(news|finance)/.*?[&]from=ucweb([&].*)?";

------解决方案--------------------
这个需用正则表达式。但是描述的不是很到位啊。

------解决方案--------------------

探讨

是匹配(/news/|/finace/)&from=ucweb，即/news或/finace后面紧跟/&from=cuweb，还是说以/news/或/finace/开头，中间可以出现任意abroad/zhuanti，然后跟着&from=cuweb，随后任意，即&foo=sthelse可有可无

have a try
Java code
String rege……