public class teetet {
    
    public static void main(String[] args){
        String s1 = "123";
        String s2 = "321";
        String s3 = "asd";
        
        for(int i = 1;i<4;i++)
        {
            System.out.println("s"+i);
        }

    }

}

package text4;

import java.util.ArrayList;
import java.util.List;

public class Demo1 {
    public static void main(String args[]){
        List<String> list = new ArrayList<String>();
        list.add("123");
        list.add("234");
        list.add("dfg");
        for(String s:list){
            System.out.println(s);
        }
    }
}

------解决方案--------------------
Java不是动态语言，所以只能。。。
Java code

    public static void main(String[] args) {
        String s1 = "123";
        String s2 = "321";
        String s3 = "asd";

        Map<String, Object> valMap = new HashMap<String, Object>();
        valMap.put("s1", s1);
        valMap.put("s2", s2);
        valMap.put("s3", s3);

        for (int i = 1; i < 4; i++) {
            System.out.println(valMap.get("s" + i));
        }
    }

------解决方案--------------------
import java.util.ArrayList;
import java.util.List;

public class teetet {
  
   public static void main(String[] args){
       String s1 = "123";
       String s2 = "321";
       String s3 = "asd";
      
      List<String> result = new ArrayList<String>();
		
		result.add(s1);
		result.add(s2);
		result.add(s3);
		
		for (int i = 0; i < 3; i++) {	
			System.out.println(result.get(i));
		}
   }

}


------解决方案--------------------

public  class teetet {

	/**
	 * @param args
	 */
	public static void main(String[] args) {
		// TODO Auto-generated method stub

		String[] s={"123","321","asd"};
		    
		        for(int i = 0;i<s.length;i++)
		        {
		            System.out.println(s[i]);
		        }
		}
}
可以用用String类型的数组赋值啊，或者用集合