Java线程的问题（执行次序的疑惑？）
程序主体如下：
package test;
public class ThreadRangbu {
public static void main(String[] args) throws Exception {
Thread01 thread01 = new Thread01();
thread01.start();
for (int i =0; i<5;i++){
try{
Thread.currentThread().sleep(100);
System.out.println(Thread.currentThread().getName() +" is executing!");
//System.out.println("i="+i);
} catch (Exception e){
}
}
}
}
class Thread01 extends Thread{
public void run(){
for (int i =0; i<5;i++){
try{
Thread.currentThread().sleep(100);
}catch(Exception e) {
e.printStackTrace();
}
System.out.println(Thread.currentThread().getName() +" is running!");
//System.out.println("i="+i);
if (i%2==0){
Thread.yield();
System.out.println("Terminate current sub-thread.");
}
}
}
}
教科书上的结论说程序运行结果应该是是：
main is executing!
Thread-0 is running!
Thread-0 is running!
main is executing!
Terminate current sub-thread.
main is executing!
Thread-0 is running!
main is executing!
Thread-0 is running!
Terminate current sub-thread.
而程序实际运行的结果如下：
Thread-0 is running!
main is executing!
Terminate current sub-thread.
Thread-0 is running!
main is executing!
Thread-0 is running!
main is executing!
Terminate current sub-thread.
main is executing!
Thread-0 is running!
Thread-0 is running!
main is executing!
Terminate current sub-thread.

疑问一： 究竟哪个结果才是正确的？

当红色字体部分取消注释时，结果如下：
main is executing!
Thread-0 is running!
i=0
Terminate current sub-thread.
main is executing!
Thread-0 is running!
i=1
main is executing!
Thread-0 is running!
i=2
Terminate current sub-thread.
main is executing!
Thread-0 is running!
i=3
main is executing!
Thread-0 is running!
i=4
Terminate current sub-thread.

疑问二：为什么会产生这个变化？

当红色和蓝色字体都取消注释时，结果如下：
Thread-0 is running!
i=0
main is executing!
i=0
Terminate current sub-thread.
main is executing!
i=1
Thread-0 is running!
i=1
Thread-0 is running!
i=2
main is executing!
i=2
Terminate current sub-thread.
Thread-0 is running!
i=3
main is executing!
i=3
Thread-0 is running!
i=4
main is executing!
i=4
Terminate current sub-thread.

疑问三：同疑问二，为什么取消注释又有了这样的变化？

总的疑问：对java中线程的执行处理次序不是很明白。以原程序为例（注释两行的程序）我的理解如下：
主方法中“Thread01 thread01 = new Thread01();thread01.start();”创建新的实例thread01,并且调用thread01中的方法run()，其中因为有“System.out.println(Thread.currentThread().getName() +" is running!");”语句，所以程序第一行应该是Thread-0 is running!
此时i=0，故返回主线程，因“System.out.println(Thread.currentThread().getName() +" is executing!");”语句，得到main is executing!
然后返回执行run()得到“Terminate current sub-thread.”结果。
之后i递增，返回main中运行程序，得到与书中不符的结果。
请问高手，我的理解是否正确？ 如果有错误，哪里理解存在问题？ 请帮我指点一下，谢谢。


------解决方案--------------------
线程的执行顺序是随机的，不确定的

可以参照《操作系统》中有关进程调度的内容
------解决方案--------------------

探讨

引用:
线程的执行顺序是随机的，不确定的

可以参照《操作系统》中有关进程调度的内容

那么请问在这个程序中，“thread01.start();”语句应该在何时执行？它的作用是什么？

------解决方案--------------------

探讨

引用:

引用:

引用:
线程的执行顺序是随机的，不确定的

可以参照《操作系统》中有关进程调度的内容

那么请问在这个程序中，“thread01.start();”语句应该在何时执行？它的作用是什么？


该调用启动线程，调用run方法就就交给新启动的线程来做了,有可能刚启动的线程就得到了CPU时间，于是运行了ru……

------解决方案--------------------