package com.ss;

import java.io.IOException;
import java.net.URL;
import java.util.List;
import org.jdom.Document;
import org.jdom.Element;
import org.jdom.JDOMException;
import org.jdom.input.SAXBuilder;

public class ParseXml
{
    public static void main(String[] args)
    {
    SAXBuilder builder = new SAXBuilder(false);
    String xml="user.xml";//这个路径表示跟当前类在同一个package下
    URL url = ParseXml.class.getResource(xml);

    Document doc;
    try
    {
        doc = builder.build(url);
        Element dataset = doc.getRootElement();
        List userList = dataset.getChildren();
        for(int i=0;i<userList.size();i++)
        {
        Element user = (Element)userList.get(i);
        Element userName =(Element)user.getChildren().get(0);
        Element password =(Element)user.getChildren().get(1);
        System.out.println("username:" +userName.getText() +"  password:"+password.getText());
        }
        
    }
    catch (JDOMException e)
    {
         e.printStackTrace();
    }
    catch (IOException e)
    {
        e.printStackTrace();
    }
    }
}

------解决方案--------------------
Java code

public static void readxmlFile() {
        String fileName = "etc/abc.xml";
        Element element = null;
        File f = new File(fileName);
        DocumentBuilder db = null;
        DocumentBuilderFactory dbf = null;
        try {
            dbf = DocumentBuilderFactory.newInstance();
            db = dbf.newDocumentBuilder();
            Document dt = db.parse(f);
            element = dt.getDocumentElement();
            NodeList childNodes = element.getChildNodes();
            String userName = "";
            String password = "";
            for (int i = 0; i < childNodes.getLength(); i++) {
                Node node1 = childNodes.item(i);
                if ("user".equals(node1.getNodeName())) {
                    NodeList nodeDetail = node1.getChildNodes(); 
                    for (int j = 0; j < nodeDetail.getLength(); j++) { // 遍历<users>下的节点
                        Node detail = nodeDetail.item(j); // 获得<users>元素每一个节点
                        if ("username".equals(detail.getNodeName())) 
                            userName = detail.getTextContent();
                        else if ("password".equals(detail.getNodeName())) {
                            password = detail.getTextContent();
                        }
                    }
                    System.out.println("userName:" + userName + " password:"
                            + password);
                }
            }

        } catch (Exception e) {
            e.printStackTrace();
        }
    }

------解决方案--------------------
可以直接使用java自带的DOM解析方式

------解决方案--------------------
dom4j xpath解析很方便

------解决方案--------------------
dom4j