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会C++和java的！啦

日期：2014-05-20　 浏览次数：20958 次

会C++和java的！求助啦！
帮忙，把下面一段c++代码转为java代码，谢啦！
C/C++ code

//笛卡尔坐标系
typedef struct tagCRDCARTESIAN
{
double x;
double y;
double z;
}CRDCARTESIAN,*PCRDCARTESIAN;
//typedef CRDCARTESIAN *PCRDCARTESIAN;

//大地坐标系
typedef struct tagCRDGEODETIC{
double longitude; //经度
double latitude;  //纬度 
double height;    //大地高,可设为0
}CRDGEODETIC;
typedef CRDGEODETIC *PCRDGEODETIC;



void CoordCovert::GeodeticToCartesian (PCRDCARTESIAN pcc, PCRDGEODETIC pcg,double dSemiMajorAxis, double dFlattening)
{ 
    double B;    //纬度度数
    double L;    //经度度数
    double L0;    //中央经线度数
    double l;    //L-L0
    double t;    //tanB
    double m;    //ltanB
    double N;    //卯酉圈曲率半径 
    double q2;
    double x;    //高斯平面纵坐标
    double y;    //高斯平面横坐标
    double s;    //赤道至纬度B的经线弧长
    double f;    //参考椭球体扁率
    double e2;    //椭球第一偏心率
    double a;    //参考椭球体长半轴
    //double b;    //参考椭球体短半轴
    double a1;
    double a2;
    double a3;
    double a4;
    double b1;
    double b2;
    double b3;
    double b4;
    double c0;
    double c1;
    double c2;
    double c3;        //投影带号
    int zonewide=3;     
    int Datum=84;    //投影基准面类型：北京54基准面为54，西安80基准面为80，WGS84基准面为84
    int prjno=0;    //
    double IPI=0.0174532925199433333333;    //3.1415926535898/180.0
    B=pcg->latitude ; //纬度
    L=pcg->longitude ; //经度
    if (zonewide==6) 
    {
         prjno=(int)(L/zonewide)+1;
         L0=prjno*zonewide-3;
    }
    else
    {
        prjno=(int)((L-1.5)/3)+1;
        L0=prjno*3;
    }
    
    if(Datum==54)
    {
         a=6378245;
         f=1/298.3;
    }    
    else if(Datum==84)
    {
        a=6378137;
        f=1/298.257223563;
    }
    L0=L0*IPI;
    L=L*IPI;
    B=B*IPI;

    e2=2*f-f*f;//(a*a-b*b)/(a*a);
    l=L-L0;
    t=tan(B);
    m=l * cos(B);
    N=a/sqrt(1-e2* sin(B) * sin(B));
    q2=e2/(1-e2)* cos(B)* cos(B);
    a1=1+(double)3/4*e2+(double)45/64*e2*e2+(double)175/256*e2*e2*e2+(double)11025/16384*e2*e2*e2*e2+(double)43659/65536*e2*e2*e2*e2*e2;
    a2=(double)3/4*e2+(double)15/16*e2*e2+(double)525/512*e2*e2*e2+(double)2205/2048*e2*e2*e2*e2+(double)72765/65536*e2*e2*e2*e2*e2;
    a3=(double)15/64*e2*e2+(double)105/256*e2*e2*e2+(double)2205/4096*e2*e2*e2*e2+(double)10359/16384*e2*e2*e2*e2*e2;
    a4=(double)35/512*e2*e2*e2+(double)315/2048*e2*e2*e2*e2+(double)31185/13072*e2*e2*e2*e2*e2;
    b1=a1*a*(1-e2);
    b2=(double)-1/2*a2*a*(1-e2);
    b3=(double)1/4*a3*a*(1-e2);
    b4=(double)-1/6*a4*a*(1-e2);
    c0=b1;
    c1=2*b2+4*b3+6*b4;
    c2=-(8*b3+32*b4);
    c3=32*b4;
    s=c0*B+cos(B)*(c1*sin(B)+c2*sin(B)*sin(B)*sin(B)+c3*sin(B)*sin(B)*sin(B)*sin(B)*sin(B));
    x=s+(double)1/2*N*t*m*m+(double)1/24*(5-t*t+9*q2+4*q2*q2)*N*t*m*m*m*m+(double)1/720*(61-58*t*t+t*t*t*t)*N*t*m*m*m*m*m*m;
    y=N*m+(double)1/6*(1-t*t+q2)*N*m*m*m+(double)1/120*(5-18*t*t+t*t*t*t-14*q2-58*q2*t*t)*N*m*m*m*m*m;
    y=y+1000000*prjno+500000;


    pcc->x=x;
    pcc->y=y-38000000;

    ->z=0;

}


------解决方案--------------------
不懂c++的路过，楼主我没学过c++,临时看了些语法。。。要不是你找我，真不想趟这趟浑水。看能用不。。。
Java code

public class CoordCovert {
    // 笛卡尔坐标系
    class CRDCARTESIAN {
        double x;

        double y;

        double z;
    };

    // 大地坐标系
    class CRDGEODETIC {
        double longitude; // 经度

        double latitude; // 纬度

        double height; // 大地高,可设为0
    }

    CRDGEODETIC PCRDGEODETIC = new CRDGEODETIC();

    CRDCARTESIAN PCRDCARTESIAN = new CRDCARTESIAN();

    void GeodeticToCartesian(CRDCARTESIAN pcc, CRDGEODETIC pcg,
            double dSemiMajorAxis, double dFlattening) {
             double B;    //纬度度数
            double L;    //经度度数
            double L0;    //中央经线度数
            double l;    //L-L0
            double t;    //tanB
            double m;    //ltanB
            double N;    //卯酉圈曲率半径 
            double q2;
            double x;    //高斯平面纵坐标
            double y;    //高斯平面横坐标
            double s;    //赤道至纬度B的经线弧长
            double f = 0;    //参考椭球体扁率
            double e2;    //椭球第一偏心率
            double a = 0;    //参考椭球体长半轴
            //double b;    //参考椭球体短半轴
            double a1;
            double a2;
            double a3;
            double a4;
            double b1;
            double b2;
            double b3;
            double b4;
            double c0;
            double c1;
            double c2;
            double c3;        //投影带号
            int zonewide=3;     
            int Datum=84;    //投影基准面类型：北京54基准面为54，西安80基准面为80，WGS84基准面为84
            int prjno=0;    //
            double IPI=0.0174532925199433333333;    //3.1415926535898/180.0
            B = pcg.latitude ; //纬度
            L = pcg.longitude ; //经度
            if (zonewide==6) 
            {
                 prjno=(int)(L/zonewide)+1;
                 L0=prjno*zonewide-3;
            }
            else
            {
                prjno=(int)((L-1.5)/3)+1;
                L0=prjno*3;
            }
            
            if(Datum==54)
            {
                 a=6378245;
                 f=1/298.3;
            }    
            else if(Datum==84)
            {
                a=6378137;
                f=1/298.257223563;
            }
            L0=L0*IPI;
            L=L*IPI;
            B=B*IPI;
            e2=2*f-f*f;//(a*a-b*b)/(a*a);
            l=L-L0;
            t=tan(B);
            m=l * cos(B);
            N=a/sqrt(1-e2* sin(B) * sin(B));
            q2=e2/(1-e2)* cos(B)* cos(B);
            a1=1+(double)3/4*e2+(double)45/64*e2*e2+(double)175/256*e2*e2*e2+(double)11025/16384*e2*e2*e2*e2+(double)43659/65536*e2*e2*e2*e2*e2;
            a2=(double)3/4*e2+(double)15/16*e2*e2+(double)525/512*e2*e2*e2+(double)2205/2048*e2*e2*e2*e2+(double)72765/65536*e2*e2*e2*e2*e2;
            a3=(double)15/64*e2*e2+(double)105/256*e2*e2*e2+(double)2205/4096*e2*e2*e2*e2+(double)10359/16384*e2*e2*e2*e2*e2;
            a4=(double)35/512*e2*e2*e2+(double)315/2048*e2*e2*e2*e2+(double)31185/13072*e2*e2*e2*e2*e2;
            b1=a1*a*(1-e2);
            b2=(double)-1/2*a2*a*(1-e2);
            b3=(double)1/4*a3*a*(1-e2);
            b4=(double)-1/6*a4*a*(1-e2);
            c0=b1;
            c1=2*b2+4*b3+6*b4;
            c2=-(8*b3+32*b4);
            c3=32*b4;
            s=c0*B+cos(B)*(c1*sin(B)+c2*sin(B)*sin(B)*sin(B)+c3*sin(B)*sin(B)*sin(B)*sin(B)*sin(B));
            x=s+(double)1/2*N*t*m*m+(double)1/24*(5-t*t+9*q2+4*q2*q2)*N*t*m*m*m*m+(double)1/720*(61-58*t*t+t*t*t*t)*N*t*m*m*m*m*m*m;
            y=N*m+(double)1/6*(1-t*t+q2)*N*m*m*m+(double)1/120*(5-18*t*t+t*t*t*t-14*q2-58*q2*t*t)*N*m*m*m*m*m;
            y=y+1000000*prjno+500000;
            pcc.x = x;
            pcc.y = y-38000000;
            pcc.z = 0;
            
    }
    double sin(double args){
        return Math.sin(args);
    }
    double cos(double args){
        return Math.cos(args);
    }
    double sqrt(double args){
        return Math.sqrt(args);
    }
    double tan(double args){
        return Math.tan(args);
    }
}

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